Using Heron's Formula To Calculate The Area Of A Triangle

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Introduction

Heron's formula is a powerful method for calculating the area of a triangle when you know the lengths of all three sides. It is particularly useful when you are unable to find the height of the triangle. In this guide, we'll explore Heron's formula and demonstrate how to use it to find the area of a triangle.


Understanding Heron's Formula

Heron's formula allows you to calculate the area \( A \) of a triangle when you know the lengths of its three sides \( a \), \( b \), and \( c \). The formula is as follows:


\[ A = \sqrt{s \times (s - a) \times (s - b) \times (s - c)} \]


Where:

- \( s \) is the semi-perimeter of the triangle, calculated as \( \frac{a + b + c}{2} \).


Heron's formula derives from Heron's theorem, which states that the area of a triangle can be determined solely from the lengths of its sides. The formula involves calculating the semi-perimeter of the triangle and then using it to find the area based on the lengths of the sides.


Step-by-Step Calculation

Let's work through an example to illustrate the process.


Example:

Suppose we have a triangle with side lengths \( a = 5 \), \( b = 7 \), and \( c = 9 \). We want to find the area of the triangle using Heron's formula.


Step 1: Calculate the Semi-Perimeter

First, calculate the semi-perimeter \( s \):


\[ s = \frac{5 + 7 + 9}{2} \]


\[ s = \frac{21}{2} \]


\[ s = 10.5 \]


Step 2: Use Heron's Formula to Find the Area

Now, substitute the values into Heron's formula:


\[ A = \sqrt{10.5 \times (10.5 - 5) \times (10.5 - 7) \times (10.5 - 9)} \]


Step 3: Perform the Calculation

Now, calculate the area:


\[ A = \sqrt{10.5 \times 5.5 \times 3.5 \times 1.5} \]


\[ A \approx \sqrt{228.5625} \]


\[ A \approx 15.125 \]


Final Value

For a triangle with side lengths \( a = 5 \), \( b = 7 \), and \( c = 9 \), the area using Heron's formula is approximately \( 15.125 \) square units.


By following these steps, you can easily determine the area of any triangle using Heron's formula.

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