Convert (gram • meter) / second to foot-pound • pound force

Learn how to convert 1 (gram • meter) / second to foot-pound • pound force step by step.

Calculation Breakdown

Set up the equation

1.0 (\frac{g r a m \times m e t e r}{s e c o n d}) = x (f o o t - p o u n d \times p o u n d f o r c e)

Define the base values of the selected units in relation to the SI unit

(j o u l e)

Left side: 1.0 (\frac{g r a m \times m e t e r}{s e c o n d}) = 10^{- 3} (j o u l e) = 10^{- 3} (J)

Right side: 1.0 (f o o t - p o u n d \times p o u n d f o r c e) = 1.3558179483314 (j o u l e) = 1.3558179483314 (J)

Insert known values into the conversion equation to determine

x

1.0 (\frac{g r a m \times m e t e r}{s e c o n d}) = x (f o o t - p o u n d \times p o u n d f o r c e)

Insert known values =>

1.0 \times 10^{- 3} \times (j o u l e) = x \times 1.3558179483314 \times (j o u l e)

Or

1.0 \cdot 10^{- 3} \cdot (J) = x \cdot 1.3558179483314 \cdot (J)

Cancel SI units

1.0 \times 10^{- 3} \cdot (J) = x \times 1.3558179483314 \times (J)

Conversion Equation

10^{- 3} = x \times 1.3558179483314

Switch sides

x \times 1.3558179483314 = 10^{- 3}

Isolate

x

Multiply both sides by

(\frac{1.0}{1.3558179483314})

x \times 1.3558179483314 \times \frac{1.0}{1.3558179483314} = 10^{- 3} \times \frac{1.0}{1.3558179483314}

Cancel

x \times 1.3558179483314 \times \frac{1.0}{1.3558179483314} = 10^{- 3} \times \frac{1.0}{1.3558179483314}

Simplify

x = \frac{10^{- 3}}{1.3558179483314}

Solve

x

x \approx 0.0007375621 \approx 7.3756 \times 10^{- 4}

Conversion Equation

1.0 (\frac{g r a m \times m e t e r}{s e c o n d}) \approx 7.3756 \times 10^{- 4} (f o o t - p o u n d \times p o u n d f o r c e)

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