Convert (gram • meter) / second to therm

Learn how to convert 1 (gram • meter) / second to therm step by step.

Calculation Breakdown

Set up the equation

1.0 (\frac{g r a m \times m e t e r}{s e c o n d}) = x (t h e r m)

Define the base values of the selected units in relation to the SI unit

(j o u l e)

Left side: 1.0 (\frac{g r a m \times m e t e r}{s e c o n d}) = 10^{- 3} (j o u l e) = 10^{- 3} (J)

Right side: 1.0 (t h e r m) = 105480400.0 (j o u l e) = 105480400.0 (J)

Insert known values into the conversion equation to determine

x

1.0 (\frac{g r a m \times m e t e r}{s e c o n d}) = x (t h e r m)

Insert known values =>

1.0 \times 10^{- 3} \times (j o u l e) = x \times 105480400.0 \times (j o u l e)

Or

1.0 \cdot 10^{- 3} \cdot (J) = x \cdot 105480400.0 \cdot (J)

Cancel SI units

1.0 \times 10^{- 3} \cdot (J) = x \times 105480400.0 \times (J)

Conversion Equation

10^{- 3} = x \times 105480400.0

Switch sides

x \times 105480400.0 = 10^{- 3}

Isolate

x

Multiply both sides by

(\frac{1.0}{105480400.0})

x \times 105480400.0 \times \frac{1.0}{105480400.0} = 10^{- 3} \times \frac{1.0}{105480400.0}

Cancel

x \times 105480400.0 \times \frac{1.0}{105480400.0} = 10^{- 3} \times \frac{1.0}{105480400.0}

Simplify

x = \frac{10^{- 3}}{105480400.0}

Solve

x

x \approx 9.4804342797 \times 10^{- 12} \approx 9.4804 \times 10^{- 12}

Conversion Equation

1.0 (\frac{g r a m \times m e t e r}{s e c o n d}) \approx 9.4804 \times 10^{- 12} (t h e r m)

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