Convert BTU / cubic foot to BTU / liter
Learn how to convert
1
BTU / cubic foot to
BTU / liter
step by step.
Calculation Breakdown
Set up the equation
\(1.0\left(\dfrac{BTU}{cubic \text{ } foot}\right)={\color{rgb(20,165,174)} x}\left(\dfrac{BTU}{liter}\right)\)
Define the base values of the selected units in relation to the SI unit \(\left(\dfrac{joule}{cubic \text{ } meter}\right)\)
\(\text{Left side: 1.0 } \left(\dfrac{BTU}{cubic \text{ } foot}\right) = {\color{rgb(89,182,91)} \dfrac{1054.5}{2.8316846592 \times 10^{-2}}\left(\dfrac{joule}{cubic \text{ } meter}\right)} = {\color{rgb(89,182,91)} \dfrac{1054.5}{2.8316846592 \times 10^{-2}}\left(\dfrac{J}{m^{3}}\right)}\)
\(\text{Right side: 1.0 } \left(\dfrac{BTU}{liter}\right) = {\color{rgb(125,164,120)} \dfrac{1055.05585262}{10^{-3}}\left(\dfrac{joule}{cubic \text{ } meter}\right)} = {\color{rgb(125,164,120)} \dfrac{1055.05585262}{10^{-3}}\left(\dfrac{J}{m^{3}}\right)}\)
Insert known values into the conversion equation to determine \({\color{rgb(20,165,174)} x}\)
\(1.0\left(\dfrac{BTU}{cubic \text{ } foot}\right)={\color{rgb(20,165,174)} x}\left(\dfrac{BTU}{liter}\right)\)
\(\text{Insert known values } =>\)
\(1.0 \times {\color{rgb(89,182,91)} \dfrac{1054.5}{2.8316846592 \times 10^{-2}}} \times {\color{rgb(89,182,91)} \left(\dfrac{joule}{cubic \text{ } meter}\right)} = {\color{rgb(20,165,174)} x} \times {\color{rgb(125,164,120)} {\color{rgb(125,164,120)} \dfrac{1055.05585262}{10^{-3}}}} \times {\color{rgb(125,164,120)} \left(\dfrac{joule}{cubic \text{ } meter}\right)}\)
\(\text{Or}\)
\(1.0 \cdot {\color{rgb(89,182,91)} \dfrac{1054.5}{2.8316846592 \times 10^{-2}}} \cdot {\color{rgb(89,182,91)} \left(\dfrac{J}{m^{3}}\right)} = {\color{rgb(20,165,174)} x} \cdot {\color{rgb(125,164,120)} \dfrac{1055.05585262}{10^{-3}}} \cdot {\color{rgb(125,164,120)} \left(\dfrac{J}{m^{3}}\right)}\)
\(\text{Cancel SI units}\)
\(1.0 \times {\color{rgb(89,182,91)} \dfrac{1054.5}{2.8316846592 \times 10^{-2}}} \cdot {\color{rgb(89,182,91)} \cancel{\left(\dfrac{J}{m^{3}}\right)}} = {\color{rgb(20,165,174)} x} \times {\color{rgb(125,164,120)} \dfrac{1055.05585262}{10^{-3}}} \times {\color{rgb(125,164,120)} \cancel{\left(\dfrac{J}{m^{3}}\right)}}\)
\(\text{Conversion Equation}\)
\(\dfrac{1054.5}{2.8316846592 \times 10^{-2}} = {\color{rgb(20,165,174)} x} \times \dfrac{1055.05585262}{10^{-3}}\)
Cancel factors on both sides
\(\text{Cancel factors}\)
\(\dfrac{1054.5}{2.8316846592 \times {\color{rgb(255,204,153)} \cancel{10^{-2}}}} = {\color{rgb(20,165,174)} x} \times \dfrac{1055.05585262}{{\color{rgb(255,204,153)} \cancelto{10^{-1}}{10^{-3}}}}\)
\(\text{Simplify}\)
\(\dfrac{1054.5}{2.8316846592} = {\color{rgb(20,165,174)} x} \times \dfrac{1055.05585262}{10^{-1}}\)
Switch sides
\({\color{rgb(20,165,174)} x} \times \dfrac{1055.05585262}{10^{-1}} = \dfrac{1054.5}{2.8316846592}\)
Isolate \({\color{rgb(20,165,174)} x}\)
Multiply both sides by \(\left(\dfrac{10^{-1}}{1055.05585262}\right)\)
\({\color{rgb(20,165,174)} x} \times \dfrac{1055.05585262}{10^{-1}} \times \dfrac{10^{-1}}{1055.05585262} = \dfrac{1054.5}{2.8316846592} \times \dfrac{10^{-1}}{1055.05585262}\)
\(\text{Cancel}\)
\({\color{rgb(20,165,174)} x} \times \dfrac{{\color{rgb(255,204,153)} \cancel{1055.05585262}} \times {\color{rgb(99,194,222)} \cancel{10^{-1}}}}{{\color{rgb(99,194,222)} \cancel{10^{-1}}} \times {\color{rgb(255,204,153)} \cancel{1055.05585262}}} = \dfrac{1054.5 \times 10^{-1}}{2.8316846592 \times 1055.05585262}\)
\(\text{Simplify}\)
\({\color{rgb(20,165,174)} x} = \dfrac{1054.5 \times 10^{-1}}{2.8316846592 \times 1055.05585262}\)
Solve \({\color{rgb(20,165,174)} x}\)
\({\color{rgb(20,165,174)} x}\approx0.0352960613\approx3.5296 \times 10^{-2}\)
\(\text{Conversion Equation}\)
\(1.0\left(\dfrac{BTU}{cubic \text{ } foot}\right)\approx{\color{rgb(20,165,174)} 3.5296 \times 10^{-2}}\left(\dfrac{BTU}{liter}\right)\)
