Convert arpent length to fermi

Learn how to convert 1 arpent length to fermi step by step.

Calculation Breakdown

Set up the equation

1.0 (a r p e n t l e n g t h) = x (f e r m i)

Define the base values of the selected units in relation to the SI unit

(m e t e r)

Left side: 1.0 (a r p e n t l e n g t h) = 58.5216 (m e t e r) = 58.5216 (m)

Right side: 1.0 (f e r m i) = 10^{- 15} (m e t e r) = 10^{- 15} (m)

Insert known values into the conversion equation to determine

x

1.0 (a r p e n t l e n g t h) = x (f e r m i)

Insert known values =>

1.0 \times 58.5216 \times (m e t e r) = x \times 10^{- 15} \times (m e t e r)

Or

1.0 \cdot 58.5216 \cdot (m) = x \cdot 10^{- 15} \cdot (m)

Cancel SI units

1.0 \times 58.5216 \cdot (m) = x \times 10^{- 15} \times (m)

Conversion Equation

58.5216 = x \times 10^{- 15}

Switch sides

x \times 10^{- 15} = 58.5216

Isolate

x

Multiply both sides by

(\frac{1.0}{10^{- 15}})

x \times 10^{- 15} \times \frac{1.0}{10^{- 15}} = 58.5216 \times \frac{1.0}{10^{- 15}}

Cancel

x \times 10^{- 15} \times \frac{1.0}{10^{- 15}} = 58.5216 \times \frac{1.0}{10^{- 15}}

Simplify

x = \frac{58.5216}{10^{- 15}}

Rewrite equation

\frac{1.0}{10^{- 15}} can be rewritten to 10^{15}

Rewrite

x = 10^{15} \times 58.5216

Solve

x

x = 5.85216 \times 10^{16} \approx 5.8522 \times 10^{16}

Conversion Equation

1.0 (a r p e n t l e n g t h) \approx 5.8522 \times 10^{16} (f e r m i)

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