Convert assay ton to jin(市斤)

Learn how to convert 1 assay ton to jin(市斤) step by step.

Calculation Breakdown

Set up the equation

1.0 (a s s a y t o n) = x (j i n (市 斤))

Define the base values of the selected units in relation to the SI unit

(k i l o g r a m)

Left side: 1.0 (a s s a y t o n) = \frac{49.0}{1.5 \times 10^{3}} (k i l o g r a m) = \frac{49.0}{1.5 \times 10^{3}} (k g)

Right side: 1.0 (j i n (市 斤)) = 5.0 \times 10^{- 1} (k i l o g r a m) = 5.0 \times 10^{- 1} (k g)

Insert known values into the conversion equation to determine

x

1.0 (a s s a y t o n) = x (j i n (市 斤))

Insert known values =>

1.0 \times \frac{49.0}{1.5 \times 10^{3}} \times (k i l o g r a m) = x \times 5.0 \times 10^{- 1} \times (k i l o g r a m)

Or

1.0 \cdot \frac{49.0}{1.5 \times 10^{3}} \cdot (k g) = x \cdot 5.0 \times 10^{- 1} \cdot (k g)

Cancel SI units

1.0 \times \frac{49.0}{1.5 \times 10^{3}} \cdot (k g) = x \times 5.0 \times 10^{- 1} \times (k g)

Conversion Equation

\frac{49.0}{1.5 \times 10^{3}} = x \times 5.0 \times 10^{- 1}

Switch sides

x \times 5.0 \times 10^{- 1} = \frac{49.0}{1.5 \times 10^{3}}

Isolate

x

Multiply both sides by

(\frac{1.0}{5.0 \times 10^{- 1}})

x \times 5.0 \times 10^{- 1} \times \frac{1.0}{5.0 \times 10^{- 1}} = \frac{49.0}{1.5 \times 10^{3}} \times \frac{1.0}{5.0 \times 10^{- 1}}

Cancel

x \times 5.0 \times 10^{- 1} \times \frac{1.0}{5.0 \times 10^{- 1}} = \frac{49.0 \times 1.0}{1.5 \times {10^{3}}^{10^{2}} \times 5.0 \times 10^{- 1}}

Simplify

x = \frac{49.0}{1.5 \times 10^{2} \times 5.0}

Rewrite equation

\frac{1.0}{10^{2}} can be rewritten to 10^{- 2}

Rewrite

x = \frac{10^{- 2} \times 49.0}{1.5 \times 5.0}

Solve

x

x \approx 0.0653333333 \approx 6.5333 \times 10^{- 2}

Conversion Equation

1.0 (a s s a y t o n) \approx 6.5333 \times 10^{- 2} (j i n (市 斤))

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