Convert bag to dalton

Learn how to convert 1 bag to dalton step by step.

Calculation Breakdown

Set up the equation

1.0 (b a g) = x (d a l t o n)

Define the base values of the selected units in relation to the SI unit

(k i l o g r a m)

Left side: 1.0 (b a g) = 60.0 (k i l o g r a m) = 60.0 (k g)

Right side: 1.0 (d a l t o n) = 1.6605390666 \times 10^{- 27} (k i l o g r a m) = 1.6605390666 \times 10^{- 27} (k g)

Insert known values into the conversion equation to determine

x

1.0 (b a g) = x (d a l t o n)

Insert known values =>

1.0 \times 60.0 \times (k i l o g r a m) = x \times 1.6605390666 \times 10^{- 27} \times (k i l o g r a m)

Or

1.0 \cdot 60.0 \cdot (k g) = x \cdot 1.6605390666 \times 10^{- 27} \cdot (k g)

Cancel SI units

1.0 \times 60.0 \cdot (k g) = x \times 1.6605390666 \times 10^{- 27} \times (k g)

Conversion Equation

60.0 = x \times 1.6605390666 \times 10^{- 27}

Switch sides

x \times 1.6605390666 \times 10^{- 27} = 60.0

Isolate

x

Multiply both sides by

(\frac{1.0}{1.6605390666 \times 10^{- 27}})

x \times 1.6605390666 \times 10^{- 27} \times \frac{1.0}{1.6605390666 \times 10^{- 27}} = 60.0 \times \frac{1.0}{1.6605390666 \times 10^{- 27}}

Cancel

x \times 1.6605390666 \times 10^{- 27} \times \frac{1.0}{1.6605390666 \times 10^{- 27}} = 60.0 \times \frac{1.0}{1.6605390666 \times 10^{- 27}}

Simplify

x = \frac{60.0}{1.6605390666 \times 10^{- 27}}

Rewrite equation

\frac{1.0}{10^{- 27}} can be rewritten to 10^{27}

Rewrite

x = \frac{10^{27} \times 60.0}{1.6605390666}

Solve

x

x \approx 3.6132844572 \times 10^{28} \approx 3.6133 \times 10^{28}

Conversion Equation

1.0 (b a g) \approx 3.6133 \times 10^{28} (d a l t o n)

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