Convert bushel to displacement ton

Learn how to convert 1 bushel to displacement ton step by step.

Calculation Breakdown

Set up the equation

1.0 (b u s h e l) = x (d i s p l a c e m e n t t o n)

Define the base values of the selected units in relation to the SI unit

(c u b i c m e t e r)

Left side: 1.0 (b u s h e l) = 3.523907016688 \times 10^{- 2} (c u b i c m e t e r) = 3.523907016688 \times 10^{- 2} (m^{3})

Right side: 1.0 (d i s p l a c e m e n t t o n) = 9.9108963072 \times 10^{- 1} (c u b i c m e t e r) = 9.9108963072 \times 10^{- 1} (m^{3})

Insert known values into the conversion equation to determine

x

1.0 (b u s h e l) = x (d i s p l a c e m e n t t o n)

Insert known values =>

1.0 \times 3.523907016688 \times 10^{- 2} \times (c u b i c m e t e r) = x \times 9.9108963072 \times 10^{- 1} \times (c u b i c m e t e r)

Or

1.0 \cdot 3.523907016688 \times 10^{- 2} \cdot (m^{3}) = x \cdot 9.9108963072 \times 10^{- 1} \cdot (m^{3})

Cancel SI units

1.0 \times 3.523907016688 \times 10^{- 2} \cdot (m^{3}) = x \times 9.9108963072 \times 10^{- 1} \times (m^{3})

Conversion Equation

3.523907016688 \times 10^{- 2} = x \times 9.9108963072 \times 10^{- 1}

Cancel factors on both sides

Cancel factors

3.523907016688 \times {10^{- 2}}^{10^{- 1}} = x \times 9.9108963072 \times 10^{- 1}

Simplify

3.523907016688 \times 10^{- 1} = x \times 9.9108963072

Switch sides

x \times 9.9108963072 = 3.523907016688 \times 10^{- 1}

Isolate

x

Multiply both sides by

(\frac{1.0}{9.9108963072})

x \times 9.9108963072 \times \frac{1.0}{9.9108963072} = 3.523907016688 \times 10^{- 1} \times \frac{1.0}{9.9108963072}

Cancel

x \times 9.9108963072 \times \frac{1.0}{9.9108963072} = 3.523907016688 \times 10^{- 1} \times \frac{1.0}{9.9108963072}

Simplify

x = \frac{3.523907016688 \times 10^{- 1}}{9.9108963072}

Solve

x

x \approx 0.0355558862 \approx 3.5556 \times 10^{- 2}

Conversion Equation

1.0 (b u s h e l) \approx 3.5556 \times 10^{- 2} (d i s p l a c e m e n t t o n)

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