Convert cubic meter of atmosphere to barrel of oil

Learn how to convert 1 cubic meter of atmosphere to barrel of oil step by step.

Calculation Breakdown

Set up the equation

1.0 (c u b i c m e t e r o f a t m o s p h e r e) = x (b a r r e l o f o i l)

Define the base values of the selected units in relation to the SI unit

(j o u l e)

Left side: 1.0 (c u b i c m e t e r o f a t m o s p h e r e) = 1.01325 \times 10^{- 4} (j o u l e) = 1.01325 \times 10^{- 4} (J)

Right side: 1.0 (b a r r e l o f o i l) = 6.1178632 \times 10^{9} (j o u l e) = 6.1178632 \times 10^{9} (J)

Insert known values into the conversion equation to determine

x

1.0 (c u b i c m e t e r o f a t m o s p h e r e) = x (b a r r e l o f o i l)

Insert known values =>

1.0 \times 1.01325 \times 10^{- 4} \times (j o u l e) = x \times 6.1178632 \times 10^{9} \times (j o u l e)

Or

1.0 \cdot 1.01325 \times 10^{- 4} \cdot (J) = x \cdot 6.1178632 \times 10^{9} \cdot (J)

Cancel SI units

1.0 \times 1.01325 \times 10^{- 4} \cdot (J) = x \times 6.1178632 \times 10^{9} \times (J)

Conversion Equation

1.01325 \times 10^{- 4} = x \times 6.1178632 \times 10^{9}

Switch sides

x \times 6.1178632 \times 10^{9} = 1.01325 \times 10^{- 4}

Isolate

x

Multiply both sides by

(\frac{1.0}{6.1178632 \times 10^{9}})

x \times 6.1178632 \times 10^{9} \times \frac{1.0}{6.1178632 \times 10^{9}} = 1.01325 \times 10^{- 4} \times \frac{1.0}{6.1178632 \times 10^{9}}

Cancel

x \times 6.1178632 \times 10^{9} \times \frac{1.0}{6.1178632 \times 10^{9}} = 1.01325 \times 10^{- 4} \times \frac{1.0}{6.1178632 \times 10^{9}}

Simplify

x = \frac{1.01325 \times 10^{- 4}}{6.1178632 \times 10^{9}}

Rewrite equation

\frac{1.0}{10^{9}} can be rewritten to 10^{- 9}

Rewrite

x = \frac{10^{- 9} \times 1.01325 \times 10^{- 4}}{6.1178632}

Simplify

x = \frac{10^{- 13} \times 1.01325}{6.1178632}

Solve

x

x \approx 1.6562155231 \times 10^{- 14} \approx 1.6562 \times 10^{- 14}

Conversion Equation

1.0 (c u b i c m e t e r o f a t m o s p h e r e) \approx 1.6562 \times 10^{- 14} (b a r r e l o f o i l)

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