Convert drop to diesel

Learn how to convert 1 drop to diesel step by step.

Calculation Breakdown

Set up the equation

1.0 (d r o p) = x (d i e s e l)

Define the base values of the selected units in relation to the SI unit

(c u b i c m e t e r)

Left side: 1.0 (d r o p) = 5.0 \times 10^{- 8} (c u b i c m e t e r) = 5.0 \times 10^{- 8} (m^{3})

Right side: 1.0 (d i e s e l) = \frac{10.0}{8.5} (c u b i c m e t e r) = \frac{10.0}{8.5} (m^{3})

Insert known values into the conversion equation to determine

x

1.0 (d r o p) = x (d i e s e l)

Insert known values =>

1.0 \times 5.0 \times 10^{- 8} \times (c u b i c m e t e r) = x \times \frac{10.0}{8.5} \times (c u b i c m e t e r)

Or

1.0 \cdot 5.0 \times 10^{- 8} \cdot (m^{3}) = x \cdot \frac{10.0}{8.5} \cdot (m^{3})

Cancel SI units

1.0 \times 5.0 \times 10^{- 8} \cdot (m^{3}) = x \times \frac{10.0}{8.5} \times (m^{3})

Conversion Equation

5.0 \times 10^{- 8} = x \times \frac{10.0}{8.5}

Switch sides

x \times \frac{10.0}{8.5} = 5.0 \times 10^{- 8}

Isolate

x

Multiply both sides by

(\frac{8.5}{10.0})

x \times \frac{10.0}{8.5} \times \frac{8.5}{10.0} = 5.0 \times 10^{- 8} \times \frac{8.5}{10.0}

Cancel

x \times \frac{10.0 \times 8.5}{8.5 \times 10.0} = 5.0 \times 10^{- 8} \times \frac{8.5}{10.0}

Simplify

x = \frac{5.0 \times 10^{- 8} \times 8.5}{10.0}

Solve

x

x = 4.25 \times 10^{- 8}

Conversion Equation

1.0 (d r o p) = 4.25 \times 10^{- 8} (d i e s e l)

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