Convert dyne • meter to pound-force • foot

Learn how to convert 1 dyne • meter to pound-force • foot step by step.

Calculation Breakdown

Set up the equation
\(1.0\left(dyne \times meter\right)={\color{rgb(20,165,174)} x}\left(pound-force \times foot\right)\)
Define the base values of the selected units in relation to the SI unit \(\left(newton \times meter\right)\)
\(\text{Left side: 1.0 } \left(dyne \times meter\right) = {\color{rgb(89,182,91)} 10^{-5}\left(newton \times meter\right)} = {\color{rgb(89,182,91)} 10^{-5}\left(N \cdot m\right)}\)
\(\text{Right side: 1.0 } \left(pound-force \times foot\right) = {\color{rgb(125,164,120)} 1.3558179483314\left(newton \times meter\right)} = {\color{rgb(125,164,120)} 1.3558179483314\left(N \cdot m\right)}\)
Insert known values into the conversion equation to determine \({\color{rgb(20,165,174)} x}\)
\(1.0\left(dyne \times meter\right)={\color{rgb(20,165,174)} x}\left(pound-force \times foot\right)\)
\(\text{Insert known values } =>\)
\(1.0 \times {\color{rgb(89,182,91)} 10^{-5}} \times {\color{rgb(89,182,91)} \left(newton \times meter\right)} = {\color{rgb(20,165,174)} x} \times {\color{rgb(125,164,120)} {\color{rgb(125,164,120)} 1.3558179483314}} \times {\color{rgb(125,164,120)} \left(newton \times meter\right)}\)
\(\text{Or}\)
\(1.0 \cdot {\color{rgb(89,182,91)} 10^{-5}} \cdot {\color{rgb(89,182,91)} \left(N \cdot m\right)} = {\color{rgb(20,165,174)} x} \cdot {\color{rgb(125,164,120)} 1.3558179483314} \cdot {\color{rgb(125,164,120)} \left(N \cdot m\right)}\)
\(\text{Cancel SI units}\)
\(1.0 \times {\color{rgb(89,182,91)} 10^{-5}} \cdot {\color{rgb(89,182,91)} \cancel{\left(N \cdot m\right)}} = {\color{rgb(20,165,174)} x} \times {\color{rgb(125,164,120)} 1.3558179483314} \times {\color{rgb(125,164,120)} \cancel{\left(N \cdot m\right)}}\)
\(\text{Conversion Equation}\)
\(10^{-5} = {\color{rgb(20,165,174)} x} \times 1.3558179483314\)
Switch sides
\({\color{rgb(20,165,174)} x} \times 1.3558179483314 = 10^{-5}\)
Isolate \({\color{rgb(20,165,174)} x}\)
Multiply both sides by \(\left(\dfrac{1.0}{1.3558179483314}\right)\)
\({\color{rgb(20,165,174)} x} \times 1.3558179483314 \times \dfrac{1.0}{1.3558179483314} = 10^{-5} \times \dfrac{1.0}{1.3558179483314}\)
\(\text{Cancel}\)
\({\color{rgb(20,165,174)} x} \times {\color{rgb(255,204,153)} \cancel{1.3558179483314}} \times \dfrac{1.0}{{\color{rgb(255,204,153)} \cancel{1.3558179483314}}} = 10^{-5} \times \dfrac{1.0}{1.3558179483314}\)
\(\text{Simplify}\)
\({\color{rgb(20,165,174)} x} = \dfrac{10^{-5}}{1.3558179483314}\)
Solve \({\color{rgb(20,165,174)} x}\)
\({\color{rgb(20,165,174)} x}\approx0.0000073756\approx7.3756 \times 10^{-6}\)
\(\text{Conversion Equation}\)
\(1.0\left(dyne \times meter\right)\approx{\color{rgb(20,165,174)} 7.3756 \times 10^{-6}}\left(pound-force \times foot\right)\)

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