Convert fall to djerib

Learn how to convert 1 fall to djerib step by step.

Calculation Breakdown

Set up the equation

1.0 (f a l l) = x (d j e r i b)

Define the base values of the selected units in relation to the SI unit

(s q u a r e m e t e r)

Left side: 1.0 (f a l l) = 47.03 (s q u a r e m e t e r) = 47.03 (m^{2})

Right side: 1.0 (d j e r i b) = 10^{4} (s q u a r e m e t e r) = 10^{4} (m^{2})

Insert known values into the conversion equation to determine

x

1.0 (f a l l) = x (d j e r i b)

Insert known values =>

1.0 \times 47.03 \times (s q u a r e m e t e r) = x \times 10^{4} \times (s q u a r e m e t e r)

Or

1.0 \cdot 47.03 \cdot (m^{2}) = x \cdot 10^{4} \cdot (m^{2})

Cancel SI units

1.0 \times 47.03 \cdot (m^{2}) = x \times 10^{4} \times (m^{2})

Conversion Equation

47.03 = x \times 10^{4}

Switch sides

x \times 10^{4} = 47.03

Isolate

x

Multiply both sides by

(\frac{1.0}{10^{4}})

x \times 10^{4} \times \frac{1.0}{10^{4}} = 47.03 \times \frac{1.0}{10^{4}}

Cancel

x \times 10^{4} \times \frac{1.0}{10^{4}} = 47.03 \times \frac{1.0}{10^{4}}

Simplify

x = \frac{47.03}{10^{4}}

Rewrite equation

\frac{1.0}{10^{4}} can be rewritten to 10^{- 4}

Rewrite

x = 10^{- 4} \times 47.03

Solve

x

x = 0.004703 = 4.703 \times 10^{- 3}

Conversion Equation

1.0 (f a l l) = 4.703 \times 10^{- 3} (d j e r i b)

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