Convert fermi to jo(丈)

Learn how to convert 1 fermi to jo(丈) step by step.

Calculation Breakdown

Set up the equation

1.0 (f e r m i) = x (j o (丈))

Define the base values of the selected units in relation to the SI unit

(m e t e r)

Left side: 1.0 (f e r m i) = 10^{- 15} (m e t e r) = 10^{- 15} (m)

Right side: 1.0 (j o (丈)) = \frac{10^{2}}{33.0} (m e t e r) = \frac{10^{2}}{33.0} (m)

Insert known values into the conversion equation to determine

x

1.0 (f e r m i) = x (j o (丈))

Insert known values =>

1.0 \times 10^{- 15} \times (m e t e r) = x \times \frac{10^{2}}{33.0} \times (m e t e r)

Or

1.0 \cdot 10^{- 15} \cdot (m) = x \cdot \frac{10^{2}}{33.0} \cdot (m)

Cancel SI units

1.0 \times 10^{- 15} \cdot (m) = x \times \frac{10^{2}}{33.0} \times (m)

Conversion Equation

10^{- 15} = x \times \frac{10^{2}}{33.0}

Switch sides

x \times \frac{10^{2}}{33.0} = 10^{- 15}

Isolate

x

Multiply both sides by

(\frac{33.0}{10^{2}})

x \times \frac{10^{2}}{33.0} \times \frac{33.0}{10^{2}} = 10^{- 15} \times \frac{33.0}{10^{2}}

Cancel

x \times \frac{10^{2} \times 33.0}{33.0 \times 10^{2}} = 10^{- 15} \times \frac{33.0}{10^{2}}

Simplify

x = \frac{10^{- 15} \times 33.0}{10^{2}}

Rewrite equation

\frac{1.0}{10^{2}} can be rewritten to 10^{- 2}

Rewrite

x = 10^{- 2} \times 10^{- 15} \times 33.0

Simplify

x = 10^{- 17} \times 33.0

Solve

x

x = 3.3 \times 10^{- 16}

Conversion Equation

1.0 (f e r m i) = 3.3 \times 10^{- 16} (j o (丈))

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