Convert firkin to liang(市兩)

Learn how to convert 1 firkin to liang(市兩) step by step.

Calculation Breakdown

Set up the equation

1.0 (f i r k i n) = x (l i a n g (市 兩))

Define the base values of the selected units in relation to the SI unit

(k i l o g r a m)

Left side: 1.0 (f i r k i n) = 25.40117272 (k i l o g r a m) = 25.40117272 (k g)

Right side: 1.0 (l i a n g (市 兩)) = 5.0 \times 10^{- 2} (k i l o g r a m) = 5.0 \times 10^{- 2} (k g)

Insert known values into the conversion equation to determine

x

1.0 (f i r k i n) = x (l i a n g (市 兩))

Insert known values =>

1.0 \times 25.40117272 \times (k i l o g r a m) = x \times 5.0 \times 10^{- 2} \times (k i l o g r a m)

Or

1.0 \cdot 25.40117272 \cdot (k g) = x \cdot 5.0 \times 10^{- 2} \cdot (k g)

Cancel SI units

1.0 \times 25.40117272 \cdot (k g) = x \times 5.0 \times 10^{- 2} \times (k g)

Conversion Equation

25.40117272 = x \times 5.0 \times 10^{- 2}

Switch sides

x \times 5.0 \times 10^{- 2} = 25.40117272

Isolate

x

Multiply both sides by

(\frac{1.0}{5.0 \times 10^{- 2}})

x \times 5.0 \times 10^{- 2} \times \frac{1.0}{5.0 \times 10^{- 2}} = 25.40117272 \times \frac{1.0}{5.0 \times 10^{- 2}}

Cancel

x \times 5.0 \times 10^{- 2} \times \frac{1.0}{5.0 \times 10^{- 2}} = 25.40117272 \times \frac{1.0}{5.0 \times 10^{- 2}}

Simplify

x = \frac{25.40117272}{5.0 \times 10^{- 2}}

Rewrite equation

\frac{1.0}{10^{- 2}} can be rewritten to 10^{2}

Rewrite

x = \frac{10^{2} \times 25.40117272}{5.0}

Solve

x

x = 508.0234544 \approx 5.0802 \times 10^{2}

Conversion Equation

1.0 (f i r k i n) \approx 5.0802 \times 10^{2} (l i a n g (市 兩))

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