Convert foot-pound • pound force to ton of coal

Learn how to convert 1 foot-pound • pound force to ton of coal step by step.

Calculation Breakdown

Set up the equation

1.0 (f o o t - p o u n d \times p o u n d f o r c e) = x (t o n o f c o a l)

Define the base values of the selected units in relation to the SI unit

(j o u l e)

Left side: 1.0 (f o o t - p o u n d \times p o u n d f o r c e) = 1.3558179483314 (j o u l e) = 1.3558179483314 (J)

Right side: 1.0 (t o n o f c o a l) = 2.9288 \times 10^{10} (j o u l e) = 2.9288 \times 10^{10} (J)

Insert known values into the conversion equation to determine

x

1.0 (f o o t - p o u n d \times p o u n d f o r c e) = x (t o n o f c o a l)

Insert known values =>

1.0 \times 1.3558179483314 \times (j o u l e) = x \times 2.9288 \times 10^{10} \times (j o u l e)

Or

1.0 \cdot 1.3558179483314 \cdot (J) = x \cdot 2.9288 \times 10^{10} \cdot (J)

Cancel SI units

1.0 \times 1.3558179483314 \cdot (J) = x \times 2.9288 \times 10^{10} \times (J)

Conversion Equation

1.3558179483314 = x \times 2.9288 \times 10^{10}

Switch sides

x \times 2.9288 \times 10^{10} = 1.3558179483314

Isolate

x

Multiply both sides by

(\frac{1.0}{2.9288 \times 10^{10}})

x \times 2.9288 \times 10^{10} \times \frac{1.0}{2.9288 \times 10^{10}} = 1.3558179483314 \times \frac{1.0}{2.9288 \times 10^{10}}

Cancel

x \times 2.9288 \times 10^{10} \times \frac{1.0}{2.9288 \times 10^{10}} = 1.3558179483314 \times \frac{1.0}{2.9288 \times 10^{10}}

Simplify

x = \frac{1.3558179483314}{2.9288 \times 10^{10}}

Rewrite equation

\frac{1.0}{10^{10}} can be rewritten to 10^{- 10}

Rewrite

x = \frac{10^{- 10} \times 1.3558179483314}{2.9288}

Solve

x

x \approx 4.6292609544 \times 10^{- 11} \approx 4.6293 \times 10^{- 11}

Conversion Equation

1.0 (f o o t - p o u n d \times p o u n d f o r c e) \approx 4.6293 \times 10^{- 11} (t o n o f c o a l)

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