Convert foot-poundal to (gram • meter) / second

Learn how to convert 1 foot-poundal to (gram • meter) / second step by step.

Calculation Breakdown

Set up the equation

1.0 (f o o t - p o u n d a l) = x (\frac{g r a m \times m e t e r}{s e c o n d})

Define the base values of the selected units in relation to the SI unit

(j o u l e)

Left side: 1.0 (f o o t - p o u n d a l) = 4.21401100938048 \times 10^{- 2} (j o u l e) = 4.21401100938048 \times 10^{- 2} (J)

Right side: 1.0 (\frac{g r a m \times m e t e r}{s e c o n d}) = 10^{- 3} (j o u l e) = 10^{- 3} (J)

Insert known values into the conversion equation to determine

x

1.0 (f o o t - p o u n d a l) = x (\frac{g r a m \times m e t e r}{s e c o n d})

Insert known values =>

1.0 \times 4.21401100938048 \times 10^{- 2} \times (j o u l e) = x \times 10^{- 3} \times (j o u l e)

Or

1.0 \cdot 4.21401100938048 \times 10^{- 2} \cdot (J) = x \cdot 10^{- 3} \cdot (J)

Cancel SI units

1.0 \times 4.21401100938048 \times 10^{- 2} \cdot (J) = x \times 10^{- 3} \times (J)

Conversion Equation

4.21401100938048 \times 10^{- 2} = x \times 10^{- 3}

Cancel factors on both sides

Cancel factors

4.21401100938048 \times 10^{- 2} = x \times {10^{- 3}}^{10^{- 1}}

Simplify

4.21401100938048 = x \times 10^{- 1}

Switch sides

x \times 10^{- 1} = 4.21401100938048

Isolate

x

Multiply both sides by

(\frac{1.0}{10^{- 1}})

x \times 10^{- 1} \times \frac{1.0}{10^{- 1}} = 4.21401100938048 \times \frac{1.0}{10^{- 1}}

Cancel

x \times 10^{- 1} \times \frac{1.0}{10^{- 1}} = 4.21401100938048 \times \frac{1.0}{10^{- 1}}

Simplify

x = \frac{4.21401100938048}{10^{- 1}}

Rewrite equation

\frac{1.0}{10^{- 1}} can be rewritten to 10

Rewrite

x = 10.0 \times 4.21401100938048

Solve

x

x \approx 42.140110094 \approx 42.1401

Conversion Equation

1.0 (f o o t - p o u n d a l) \approx 42.1401 (\frac{g r a m \times m e t e r}{s e c o n d})

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