Convert football field to juchart
Learn how to convert
1
football field to
juchart
step by step.
Calculation Breakdown
Set up the equation
\(1.0\left(football \text{ } field\right)={\color{rgb(20,165,174)} x}\left(juchart\right)\)
Define the base values of the selected units in relation to the SI unit \(\left(square \text{ } meter\right)\)
\(\text{Left side: 1.0 } \left(football \text{ } field\right) = {\color{rgb(89,182,91)} 8.15 \times 10^{3}\left(square \text{ } meter\right)} = {\color{rgb(89,182,91)} 8.15 \times 10^{3}\left(m^{2}\right)}\)
\(\text{Right side: 1.0 } \left(juchart\right) = {\color{rgb(125,164,120)} 4.5 \times 10^{3}\left(square \text{ } meter\right)} = {\color{rgb(125,164,120)} 4.5 \times 10^{3}\left(m^{2}\right)}\)
Insert known values into the conversion equation to determine \({\color{rgb(20,165,174)} x}\)
\(1.0\left(football \text{ } field\right)={\color{rgb(20,165,174)} x}\left(juchart\right)\)
\(\text{Insert known values } =>\)
\(1.0 \times {\color{rgb(89,182,91)} 8.15 \times 10^{3}} \times {\color{rgb(89,182,91)} \left(square \text{ } meter\right)} = {\color{rgb(20,165,174)} x} \times {\color{rgb(125,164,120)} {\color{rgb(125,164,120)} 4.5 \times 10^{3}}} \times {\color{rgb(125,164,120)} \left(square \text{ } meter\right)}\)
\(\text{Or}\)
\(1.0 \cdot {\color{rgb(89,182,91)} 8.15 \times 10^{3}} \cdot {\color{rgb(89,182,91)} \left(m^{2}\right)} = {\color{rgb(20,165,174)} x} \cdot {\color{rgb(125,164,120)} 4.5 \times 10^{3}} \cdot {\color{rgb(125,164,120)} \left(m^{2}\right)}\)
\(\text{Cancel SI units}\)
\(1.0 \times {\color{rgb(89,182,91)} 8.15 \times 10^{3}} \cdot {\color{rgb(89,182,91)} \cancel{\left(m^{2}\right)}} = {\color{rgb(20,165,174)} x} \times {\color{rgb(125,164,120)} 4.5 \times 10^{3}} \times {\color{rgb(125,164,120)} \cancel{\left(m^{2}\right)}}\)
\(\text{Conversion Equation}\)
\(8.15 \times 10^{3} = {\color{rgb(20,165,174)} x} \times 4.5 \times 10^{3}\)
Cancel factors on both sides
\(\text{Cancel factors}\)
\(8.15 \times {\color{rgb(255,204,153)} \cancel{10^{3}}} = {\color{rgb(20,165,174)} x} \times 4.5 \times {\color{rgb(255,204,153)} \cancel{10^{3}}}\)
\(\text{Simplify}\)
\(8.15 = {\color{rgb(20,165,174)} x} \times 4.5\)
Switch sides
\({\color{rgb(20,165,174)} x} \times 4.5 = 8.15\)
Isolate \({\color{rgb(20,165,174)} x}\)
Multiply both sides by \(\left(\dfrac{1.0}{4.5}\right)\)
\({\color{rgb(20,165,174)} x} \times 4.5 \times \dfrac{1.0}{4.5} = 8.15 \times \dfrac{1.0}{4.5}\)
\(\text{Cancel}\)
\({\color{rgb(20,165,174)} x} \times {\color{rgb(255,204,153)} \cancel{4.5}} \times \dfrac{1.0}{{\color{rgb(255,204,153)} \cancel{4.5}}} = 8.15 \times \dfrac{1.0}{4.5}\)
\(\text{Simplify}\)
\({\color{rgb(20,165,174)} x} = \dfrac{8.15}{4.5}\)
Solve \({\color{rgb(20,165,174)} x}\)
\({\color{rgb(20,165,174)} x}\approx1.8111111111\approx1.8111\)
\(\text{Conversion Equation}\)
\(1.0\left(football \text{ } field\right)\approx{\color{rgb(20,165,174)} 1.8111}\left(juchart\right)\)
