Convert gallon to petrol

Learn how to convert 1 gallon to petrol step by step.

Calculation Breakdown

Set up the equation

1.0 (g a l l o n) = x (p e t r o l)

Define the base values of the selected units in relation to the SI unit

(c u b i c m e t e r)

Left side: 1.0 (g a l l o n) = 4.54609 \times 10^{- 3} (c u b i c m e t e r) = 4.54609 \times 10^{- 3} (m^{3})

Right side: 1.0 (p e t r o l) = \frac{10.0}{7.2} (c u b i c m e t e r) = \frac{10.0}{7.2} (m^{3})

Insert known values into the conversion equation to determine

x

1.0 (g a l l o n) = x (p e t r o l)

Insert known values =>

1.0 \times 4.54609 \times 10^{- 3} \times (c u b i c m e t e r) = x \times \frac{10.0}{7.2} \times (c u b i c m e t e r)

Or

1.0 \cdot 4.54609 \times 10^{- 3} \cdot (m^{3}) = x \cdot \frac{10.0}{7.2} \cdot (m^{3})

Cancel SI units

1.0 \times 4.54609 \times 10^{- 3} \cdot (m^{3}) = x \times \frac{10.0}{7.2} \times (m^{3})

Conversion Equation

4.54609 \times 10^{- 3} = x \times \frac{10.0}{7.2}

Switch sides

x \times \frac{10.0}{7.2} = 4.54609 \times 10^{- 3}

Isolate

x

Multiply both sides by

(\frac{7.2}{10.0})

x \times \frac{10.0}{7.2} \times \frac{7.2}{10.0} = 4.54609 \times 10^{- 3} \times \frac{7.2}{10.0}

Cancel

x \times \frac{10.0 \times 7.2}{7.2 \times 10.0} = 4.54609 \times 10^{- 3} \times \frac{7.2}{10.0}

Simplify

x = \frac{4.54609 \times 10^{- 3} \times 7.2}{10.0}

Solve

x

x = 0.0032731848 \approx 3.2732 \times 10^{- 3}

Conversion Equation

1.0 (g a l l o n) \approx 3.2732 \times 10^{- 3} (p e t r o l)

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