Convert gram / barrel to pound / barrel

Learn how to convert 1 gram / barrel to pound / barrel step by step.

Calculation Breakdown

Set up the equation

1.0 (\frac{g r a m}{b a r r e l}) = x (\frac{p o u n d}{b a r r e l})

Define the base values of the selected units in relation to the SI unit

(\frac{k i l o g r a m}{c u b i c m e t e r})

Left side: 1.0 (\frac{g r a m}{b a r r e l}) = \frac{10^{- 2}}{1.6365924} (\frac{k i l o g r a m}{c u b i c m e t e r}) = \frac{10^{- 2}}{1.6365924} (\frac{k g}{m^{3}})

Right side: 1.0 (\frac{p o u n d}{b a r r e l}) = \frac{5.0}{1.6365924} (\frac{k i l o g r a m}{c u b i c m e t e r}) = \frac{5.0}{1.6365924} (\frac{k g}{m^{3}})

Insert known values into the conversion equation to determine

x

1.0 (\frac{g r a m}{b a r r e l}) = x (\frac{p o u n d}{b a r r e l})

Insert known values =>

1.0 \times \frac{10^{- 2}}{1.6365924} \times (\frac{k i l o g r a m}{c u b i c m e t e r}) = x \times \frac{5.0}{1.6365924} \times (\frac{k i l o g r a m}{c u b i c m e t e r})

Or

1.0 \cdot \frac{10^{- 2}}{1.6365924} \cdot (\frac{k g}{m^{3}}) = x \cdot \frac{5.0}{1.6365924} \cdot (\frac{k g}{m^{3}})

Cancel SI units

1.0 \times \frac{10^{- 2}}{1.6365924} \cdot (\frac{k g}{m^{3}}) = x \times \frac{5.0}{1.6365924} \times (\frac{k g}{m^{3}})

Conversion Equation

\frac{10^{- 2}}{1.6365924} = x \times \frac{5.0}{1.6365924}

Cancel factors on both sides

Cancel factors

\frac{10^{- 2}}{1.6365924} = x \times \frac{5.0}{1.6365924}

Simplify

10^{- 2} = x \times 5.0

Switch sides

x \times 5.0 = 10^{- 2}

Isolate

x

Multiply both sides by

(\frac{1.0}{5.0})

x \times 5.0 \times \frac{1.0}{5.0} = 10^{- 2} \times \frac{1.0}{5.0}

Cancel

x \times 5.0 \times \frac{1.0}{5.0} = 10^{- 2} \times \frac{1.0}{5.0}

Simplify

x = \frac{10^{- 2}}{5.0}

Solve

x

x = 2 \times 10^{- 3}

Conversion Equation

1.0 (\frac{g r a m}{b a r r e l}) = 2 \times 10^{- 3} (\frac{p o u n d}{b a r r e l})

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