Convert gram / barrel to pound / cubic yard
Learn how to convert
1
gram / barrel to
pound / cubic yard
step by step.
Calculation Breakdown
Set up the equation
\(1.0\left(\dfrac{gram}{barrel}\right)={\color{rgb(20,165,174)} x}\left(\dfrac{pound}{cubic \text{ } yard}\right)\)
Define the base values of the selected units in relation to the SI unit \(\left(\dfrac{{\color{rgb(230,179,255)} kilo}gram}{cubic \text{ } meter}\right)\)
\(\text{Left side: 1.0 } \left(\dfrac{gram}{barrel}\right) = {\color{rgb(89,182,91)} \dfrac{10^{-2}}{1.6365924}\left(\dfrac{{\color{rgb(230,179,255)} kilo}gram}{cubic \text{ } meter}\right)} = {\color{rgb(89,182,91)} \dfrac{10^{-2}}{1.6365924}\left(\dfrac{{\color{rgb(230,179,255)} k}g}{m^{3}}\right)}\)
\(\text{Right side: 1.0 } \left(\dfrac{pound}{cubic \text{ } yard}\right) = {\color{rgb(125,164,120)} \dfrac{5.0}{7.64554857984}\left(\dfrac{{\color{rgb(230,179,255)} kilo}gram}{cubic \text{ } meter}\right)} = {\color{rgb(125,164,120)} \dfrac{5.0}{7.64554857984}\left(\dfrac{{\color{rgb(230,179,255)} k}g}{m^{3}}\right)}\)
Insert known values into the conversion equation to determine \({\color{rgb(20,165,174)} x}\)
\(1.0\left(\dfrac{gram}{barrel}\right)={\color{rgb(20,165,174)} x}\left(\dfrac{pound}{cubic \text{ } yard}\right)\)
\(\text{Insert known values } =>\)
\(1.0 \times {\color{rgb(89,182,91)} \dfrac{10^{-2}}{1.6365924}} \times {\color{rgb(89,182,91)} \left(\dfrac{{\color{rgb(230,179,255)} kilo}gram}{cubic \text{ } meter}\right)} = {\color{rgb(20,165,174)} x} \times {\color{rgb(125,164,120)} {\color{rgb(125,164,120)} \dfrac{5.0}{7.64554857984}}} \times {\color{rgb(125,164,120)} \left(\dfrac{{\color{rgb(230,179,255)} kilo}gram}{cubic \text{ } meter}\right)}\)
\(\text{Or}\)
\(1.0 \cdot {\color{rgb(89,182,91)} \dfrac{10^{-2}}{1.6365924}} \cdot {\color{rgb(89,182,91)} \left(\dfrac{{\color{rgb(230,179,255)} k}g}{m^{3}}\right)} = {\color{rgb(20,165,174)} x} \cdot {\color{rgb(125,164,120)} \dfrac{5.0}{7.64554857984}} \cdot {\color{rgb(125,164,120)} \left(\dfrac{{\color{rgb(230,179,255)} k}g}{m^{3}}\right)}\)
\(\text{Cancel SI units}\)
\(1.0 \times {\color{rgb(89,182,91)} \dfrac{10^{-2}}{1.6365924}} \cdot {\color{rgb(89,182,91)} \cancel{\left(\dfrac{{\color{rgb(230,179,255)} k}g}{m^{3}}\right)}} = {\color{rgb(20,165,174)} x} \times {\color{rgb(125,164,120)} \dfrac{5.0}{7.64554857984}} \times {\color{rgb(125,164,120)} \cancel{\left(\dfrac{{\color{rgb(230,179,255)} k}g}{m^{3}}\right)}}\)
\(\text{Conversion Equation}\)
\(\dfrac{10^{-2}}{1.6365924} = {\color{rgb(20,165,174)} x} \times \dfrac{5.0}{7.64554857984}\)
Switch sides
\({\color{rgb(20,165,174)} x} \times \dfrac{5.0}{7.64554857984} = \dfrac{10^{-2}}{1.6365924}\)
Isolate \({\color{rgb(20,165,174)} x}\)
Multiply both sides by \(\left(\dfrac{7.64554857984}{5.0}\right)\)
\({\color{rgb(20,165,174)} x} \times \dfrac{5.0}{7.64554857984} \times \dfrac{7.64554857984}{5.0} = \dfrac{10^{-2}}{1.6365924} \times \dfrac{7.64554857984}{5.0}\)
\(\text{Cancel}\)
\({\color{rgb(20,165,174)} x} \times \dfrac{{\color{rgb(255,204,153)} \cancel{5.0}} \times {\color{rgb(99,194,222)} \cancel{7.64554857984}}}{{\color{rgb(99,194,222)} \cancel{7.64554857984}} \times {\color{rgb(255,204,153)} \cancel{5.0}}} = \dfrac{10^{-2} \times 7.64554857984}{1.6365924 \times 5.0}\)
\(\text{Simplify}\)
\({\color{rgb(20,165,174)} x} = \dfrac{10^{-2} \times 7.64554857984}{1.6365924 \times 5.0}\)
Solve \({\color{rgb(20,165,174)} x}\)
\({\color{rgb(20,165,174)} x}\approx0.0093432532\approx9.3433 \times 10^{-3}\)
\(\text{Conversion Equation}\)
\(1.0\left(\dfrac{gram}{barrel}\right)\approx{\color{rgb(20,165,174)} 9.3433 \times 10^{-3}}\left(\dfrac{pound}{cubic \text{ } yard}\right)\)
