Convert gram / cubic foot to ton / bushel

Learn how to convert 1 gram / cubic foot to ton / bushel step by step.

Calculation Breakdown

Set up the equation

1.0 (\frac{g r a m}{c u b i c f o o t}) = x (\frac{t o n}{b u s h e l})

Define the base values of the selected units in relation to the SI unit

(\frac{k i l o g r a m}{c u b i c m e t e r})

Left side: 1.0 (\frac{g r a m}{c u b i c f o o t}) = \frac{1.0}{28.316846592} (\frac{k i l o g r a m}{c u b i c m e t e r}) = \frac{1.0}{28.316846592} (\frac{k g}{m^{3}})

Right side: 1.0 (\frac{t o n}{b u s h e l}) = \frac{10^{5}}{3.636872} (\frac{k i l o g r a m}{c u b i c m e t e r}) = \frac{10^{5}}{3.636872} (\frac{k g}{m^{3}})

Insert known values into the conversion equation to determine

x

1.0 (\frac{g r a m}{c u b i c f o o t}) = x (\frac{t o n}{b u s h e l})

Insert known values =>

1.0 \times \frac{1.0}{28.316846592} \times (\frac{k i l o g r a m}{c u b i c m e t e r}) = x \times \frac{10^{5}}{3.636872} \times (\frac{k i l o g r a m}{c u b i c m e t e r})

Or

1.0 \cdot \frac{1.0}{28.316846592} \cdot (\frac{k g}{m^{3}}) = x \cdot \frac{10^{5}}{3.636872} \cdot (\frac{k g}{m^{3}})

Cancel SI units

1.0 \times \frac{1.0}{28.316846592} \cdot (\frac{k g}{m^{3}}) = x \times \frac{10^{5}}{3.636872} \times (\frac{k g}{m^{3}})

Conversion Equation

\frac{1.0}{28.316846592} = x \times \frac{10^{5}}{3.636872}

Switch sides

x \times \frac{10^{5}}{3.636872} = \frac{1.0}{28.316846592}

Isolate

x

Multiply both sides by

(\frac{3.636872}{10^{5}})

x \times \frac{10^{5}}{3.636872} \times \frac{3.636872}{10^{5}} = \frac{1.0}{28.316846592} \times \frac{3.636872}{10^{5}}

Cancel

x \times \frac{10^{5} \times 3.636872}{3.636872 \times 10^{5}} = \frac{1.0 \times 3.636872}{28.316846592 \times 10^{5}}

Simplify

x = \frac{3.636872}{28.316846592 \times 10^{5}}

Rewrite equation

\frac{1.0}{10^{5}} can be rewritten to 10^{- 5}

Rewrite

x = \frac{10^{- 5} \times 3.636872}{28.316846592}

Solve

x

x \approx 0.0000012843 \approx 1.2843 \times 10^{- 6}

Conversion Equation

1.0 (\frac{g r a m}{c u b i c f o o t}) \approx 1.2843 \times 10^{- 6} (\frac{t o n}{b u s h e l})

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