Convert gram / hour to tonne / hour

Learn how to convert 1 gram / hour to tonne / hour step by step.

Calculation Breakdown

Set up the equation

1.0 (\frac{g r a m}{h o u r}) = x (\frac{t o n n e}{h o u r})

Define the base values of the selected units in relation to the SI unit

(\frac{k i l o g r a m}{s e c o n d})

Left side: 1.0 (\frac{g r a m}{h o u r}) = \frac{10^{- 3}}{3.6 \times 10^{3}} (\frac{k i l o g r a m}{s e c o n d}) = \frac{10^{- 3}}{3.6 \times 10^{3}} (\frac{k g}{s})

Right side: 1.0 (\frac{t o n n e}{h o u r}) = \frac{907.18474}{3.6 \times 10^{3}} (\frac{k i l o g r a m}{s e c o n d}) = \frac{907.18474}{3.6 \times 10^{3}} (\frac{k g}{s})

Insert known values into the conversion equation to determine

x

1.0 (\frac{g r a m}{h o u r}) = x (\frac{t o n n e}{h o u r})

Insert known values =>

1.0 \times \frac{10^{- 3}}{3.6 \times 10^{3}} \times (\frac{k i l o g r a m}{s e c o n d}) = x \times \frac{907.18474}{3.6 \times 10^{3}} \times (\frac{k i l o g r a m}{s e c o n d})

Or

1.0 \cdot \frac{10^{- 3}}{3.6 \times 10^{3}} \cdot (\frac{k g}{s}) = x \cdot \frac{907.18474}{3.6 \times 10^{3}} \cdot (\frac{k g}{s})

Cancel SI units

1.0 \times \frac{10^{- 3}}{3.6 \times 10^{3}} \cdot (\frac{k g}{s}) = x \times \frac{907.18474}{3.6 \times 10^{3}} \times (\frac{k g}{s})

Conversion Equation

\frac{10^{- 3}}{3.6 \times 10^{3}} = x \times \frac{907.18474}{3.6 \times 10^{3}}

Cancel factors on both sides

Cancel factors

\frac{10^{- 3}}{3.6 \times 10^{3}} = x \times \frac{907.18474}{3.6 \times 10^{3}}

Simplify

10^{- 3} = x \times 907.18474

Switch sides

x \times 907.18474 = 10^{- 3}

Isolate

x

Multiply both sides by

(\frac{1.0}{907.18474})

x \times 907.18474 \times \frac{1.0}{907.18474} = 10^{- 3} \times \frac{1.0}{907.18474}

Cancel

x \times 907.18474 \times \frac{1.0}{907.18474} = 10^{- 3} \times \frac{1.0}{907.18474}

Simplify

x = \frac{10^{- 3}}{907.18474}

Solve

x

x \approx 0.0000011023 \approx 1.1023 \times 10^{- 6}

Conversion Equation

1.0 (\frac{g r a m}{h o u r}) \approx 1.1023 \times 10^{- 6} (\frac{t o n n e}{h o u r})

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