Convert gram / liter to gram / barrel

Learn how to convert 1 gram / liter to gram / barrel step by step.

Calculation Breakdown

Set up the equation

1.0 (\frac{g r a m}{l i t e r}) = x (\frac{g r a m}{b a r r e l})

Define the base values of the selected units in relation to the SI unit

(\frac{k i l o g r a m}{c u b i c m e t e r})

Left side: 1.0 (\frac{g r a m}{l i t e r}) = 1.0 (\frac{k i l o g r a m}{c u b i c m e t e r}) = 1.0 (\frac{k g}{m^{3}})

Right side: 1.0 (\frac{g r a m}{b a r r e l}) = \frac{10^{- 2}}{1.19240471196} (\frac{k i l o g r a m}{c u b i c m e t e r}) = \frac{10^{- 2}}{1.19240471196} (\frac{k g}{m^{3}})

Insert known values into the conversion equation to determine

x

1.0 (\frac{g r a m}{l i t e r}) = x (\frac{g r a m}{b a r r e l})

Insert known values =>

1.0 \times 1.0 \times (\frac{k i l o g r a m}{c u b i c m e t e r}) = x \times \frac{10^{- 2}}{1.19240471196} \times (\frac{k i l o g r a m}{c u b i c m e t e r})

Or

1.0 \cdot 1.0 \cdot (\frac{k g}{m^{3}}) = x \cdot \frac{10^{- 2}}{1.19240471196} \cdot (\frac{k g}{m^{3}})

Cancel SI units

1.0 \times 1.0 \cdot (\frac{k g}{m^{3}}) = x \times \frac{10^{- 2}}{1.19240471196} \times (\frac{k g}{m^{3}})

Conversion Equation

1.0 = x \times \frac{10^{- 2}}{1.19240471196}

Simplify

1.0 = x \times \frac{10^{- 2}}{1.19240471196}

Switch sides

x \times \frac{10^{- 2}}{1.19240471196} = 1.0

Isolate

x

Multiply both sides by

(\frac{1.19240471196}{10^{- 2}})

x \times \frac{10^{- 2}}{1.19240471196} \times \frac{1.19240471196}{10^{- 2}} = 1.0 \times \frac{1.19240471196}{10^{- 2}}

Cancel

x \times \frac{10^{- 2} \times 1.19240471196}{1.19240471196 \times 10^{- 2}} = 1.0 \times \frac{1.19240471196}{10^{- 2}}

Simplify

x = \frac{1.19240471196}{10^{- 2}}

Rewrite equation

\frac{1.0}{10^{- 2}} can be rewritten to 10^{2}

Rewrite

x = 10^{2} \times 1.19240471196

Solve

x

x \approx 119.2404712 \approx 1.1924 \times 10^{2}

Conversion Equation

1.0 (\frac{g r a m}{l i t e r}) \approx 1.1924 \times 10^{2} (\frac{g r a m}{b a r r e l})

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