Convert inch / (minute • second) to gravity

Learn how to convert 1 inch / (minute • second) to gravity step by step.

Calculation Breakdown

Set up the equation

1.0 (\frac{i n c h}{m i n u t e \times s e c o n d}) = x (g r a v i t y)

Define the base values of the selected units in relation to the SI unit

(\frac{m e t e r}{s q u a r e s e c o n d})

Left side: 1.0 (\frac{i n c h}{m i n u t e \times s e c o n d}) = \frac{2.54 \times 10^{- 2}}{60.0} (\frac{m e t e r}{s q u a r e s e c o n d}) = \frac{2.54 \times 10^{- 2}}{60.0} (\frac{m}{s^{2}})

Right side: 1.0 (g r a v i t y) = 9.80665 (\frac{m e t e r}{s q u a r e s e c o n d}) = 9.80665 (\frac{m}{s^{2}})

Insert known values into the conversion equation to determine

x

1.0 (\frac{i n c h}{m i n u t e \times s e c o n d}) = x (g r a v i t y)

Insert known values =>

1.0 \times \frac{2.54 \times 10^{- 2}}{60.0} \times (\frac{m e t e r}{s q u a r e s e c o n d}) = x \times 9.80665 \times (\frac{m e t e r}{s q u a r e s e c o n d})

Or

1.0 \cdot \frac{2.54 \times 10^{- 2}}{60.0} \cdot (\frac{m}{s^{2}}) = x \cdot 9.80665 \cdot (\frac{m}{s^{2}})

Cancel SI units

1.0 \times \frac{2.54 \times 10^{- 2}}{60.0} \cdot (\frac{m}{s^{2}}) = x \times 9.80665 \times (\frac{m}{s^{2}})

Conversion Equation

\frac{2.54 \times 10^{- 2}}{60.0} = x \times 9.80665

Switch sides

x \times 9.80665 = \frac{2.54 \times 10^{- 2}}{60.0}

Isolate

x

Multiply both sides by

(\frac{1.0}{9.80665})

x \times 9.80665 \times \frac{1.0}{9.80665} = \frac{2.54 \times 10^{- 2}}{60.0} \times \frac{1.0}{9.80665}

Cancel

x \times 9.80665 \times \frac{1.0}{9.80665} = \frac{2.54 \times 10^{- 2} \times 1.0}{60.0 \times 9.80665}

Simplify

x = \frac{2.54 \times 10^{- 2}}{60.0 \times 9.80665}

Solve

x

x \approx 0.000043168 \approx 4.3168 \times 10^{- 5}

Conversion Equation

1.0 (\frac{i n c h}{m i n u t e \times s e c o n d}) \approx 4.3168 \times 10^{- 5} (g r a v i t y)

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