# Convert jin(市斤) to last

Learn how to convert 1 jin(市斤) to last step by step.

## Calculation Breakdown

Set up the equation
$$1.0\left(jin(市斤)\right)={\color{rgb(20,165,174)} x}\left(last\right)$$
Define the base values of the selected units in relation to the SI unit $$\left({\color{rgb(230,179,255)} kilo}gram\right)$$
$$\text{Left side: 1.0 } \left(jin(市斤)\right) = {\color{rgb(89,182,91)} 5.0 \times 10^{-1}\left({\color{rgb(230,179,255)} kilo}gram\right)} = {\color{rgb(89,182,91)} 5.0 \times 10^{-1}\left({\color{rgb(230,179,255)} k}g\right)}$$
$$\text{Right side: 1.0 } \left(last\right) = {\color{rgb(125,164,120)} 1981.29147216\left({\color{rgb(230,179,255)} kilo}gram\right)} = {\color{rgb(125,164,120)} 1981.29147216\left({\color{rgb(230,179,255)} k}g\right)}$$
Insert known values into the conversion equation to determine $${\color{rgb(20,165,174)} x}$$
$$1.0\left(jin(市斤)\right)={\color{rgb(20,165,174)} x}\left(last\right)$$
$$\text{Insert known values } =>$$
$$1.0 \times {\color{rgb(89,182,91)} 5.0 \times 10^{-1}} \times {\color{rgb(89,182,91)} \left({\color{rgb(230,179,255)} kilo}gram\right)} = {\color{rgb(20,165,174)} x} \times {\color{rgb(125,164,120)} {\color{rgb(125,164,120)} 1981.29147216}} \times {\color{rgb(125,164,120)} \left({\color{rgb(230,179,255)} kilo}gram\right)}$$
$$\text{Or}$$
$$1.0 \cdot {\color{rgb(89,182,91)} 5.0 \times 10^{-1}} \cdot {\color{rgb(89,182,91)} \left({\color{rgb(230,179,255)} k}g\right)} = {\color{rgb(20,165,174)} x} \cdot {\color{rgb(125,164,120)} 1981.29147216} \cdot {\color{rgb(125,164,120)} \left({\color{rgb(230,179,255)} k}g\right)}$$
$$\text{Cancel SI units}$$
$$1.0 \times {\color{rgb(89,182,91)} 5.0 \times 10^{-1}} \cdot {\color{rgb(89,182,91)} \cancel{\left({\color{rgb(230,179,255)} k}g\right)}} = {\color{rgb(20,165,174)} x} \times {\color{rgb(125,164,120)} 1981.29147216} \times {\color{rgb(125,164,120)} \cancel{\left({\color{rgb(230,179,255)} k}g\right)}}$$
$$\text{Conversion Equation}$$
$$5.0 \times 10^{-1} = {\color{rgb(20,165,174)} x} \times 1981.29147216$$
Switch sides
$${\color{rgb(20,165,174)} x} \times 1981.29147216 = 5.0 \times 10^{-1}$$
Isolate $${\color{rgb(20,165,174)} x}$$
Multiply both sides by $$\left(\dfrac{1.0}{1981.29147216}\right)$$
$${\color{rgb(20,165,174)} x} \times 1981.29147216 \times \dfrac{1.0}{1981.29147216} = 5.0 \times 10^{-1} \times \dfrac{1.0}{1981.29147216}$$
$$\text{Cancel}$$
$${\color{rgb(20,165,174)} x} \times {\color{rgb(255,204,153)} \cancel{1981.29147216}} \times \dfrac{1.0}{{\color{rgb(255,204,153)} \cancel{1981.29147216}}} = 5.0 \times 10^{-1} \times \dfrac{1.0}{1981.29147216}$$
$$\text{Simplify}$$
$${\color{rgb(20,165,174)} x} = \dfrac{5.0 \times 10^{-1}}{1981.29147216}$$
Solve $${\color{rgb(20,165,174)} x}$$
$${\color{rgb(20,165,174)} x}\approx0.0002523606\approx2.5236 \times 10^{-4}$$
$$\text{Conversion Equation}$$
$$1.0\left(jin(市斤)\right)\approx{\color{rgb(20,165,174)} 2.5236 \times 10^{-4}}\left(last\right)$$