Convert jin(市斤) to point

Learn how to convert 1 jin(市斤) to point step by step.

Calculation Breakdown

Set up the equation

1.0 (j i n (市 斤)) = x (p o i n t)

Define the base values of the selected units in relation to the SI unit

(k i l o g r a m)

Left side: 1.0 (j i n (市 斤)) = 5.0 \times 10^{- 1} (k i l o g r a m) = 5.0 \times 10^{- 1} (k g)

Right side: 1.0 (p o i n t) = 2.0 \times 10^{- 6} (k i l o g r a m) = 2.0 \times 10^{- 6} (k g)

Insert known values into the conversion equation to determine

x

1.0 (j i n (市 斤)) = x (p o i n t)

Insert known values =>

1.0 \times 5.0 \times 10^{- 1} \times (k i l o g r a m) = x \times 2.0 \times 10^{- 6} \times (k i l o g r a m)

Or

1.0 \cdot 5.0 \times 10^{- 1} \cdot (k g) = x \cdot 2.0 \times 10^{- 6} \cdot (k g)

Cancel SI units

1.0 \times 5.0 \times 10^{- 1} \cdot (k g) = x \times 2.0 \times 10^{- 6} \times (k g)

Conversion Equation

5.0 \times 10^{- 1} = x \times 2.0 \times 10^{- 6}

Cancel factors on both sides

Cancel factors

5.0 \times 10^{- 1} = x \times 2.0 \times {10^{- 6}}^{10^{- 5}}

Simplify

5.0 = x \times 2.0 \times 10^{- 5}

Switch sides

x \times 2.0 \times 10^{- 5} = 5.0

Isolate

x

Multiply both sides by

(\frac{1.0}{2.0 \times 10^{- 5}})

x \times 2.0 \times 10^{- 5} \times \frac{1.0}{2.0 \times 10^{- 5}} = 5.0 \times \frac{1.0}{2.0 \times 10^{- 5}}

Cancel

x \times 2.0 \times 10^{- 5} \times \frac{1.0}{2.0 \times 10^{- 5}} = 5.0 \times \frac{1.0}{2.0 \times 10^{- 5}}

Simplify

x = \frac{5.0}{2.0 \times 10^{- 5}}

Rewrite equation

\frac{1.0}{10^{- 5}} can be rewritten to 10^{5}

Rewrite

x = \frac{10^{5} \times 5.0}{2.0}

Solve

x

x = 250000 = 2.5 \times 10^{5}

Conversion Equation

1.0 (j i n (市 斤)) = 2.5 \times 10^{5} (p o i n t)

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