Convert liang(市兩) to assay ton

Learn how to convert 1 liang(市兩) to assay ton step by step.

Calculation Breakdown

Set up the equation

1.0 (l i a n g (市 兩)) = x (a s s a y t o n)

Define the base values of the selected units in relation to the SI unit

(k i l o g r a m)

Left side: 1.0 (l i a n g (市 兩)) = 5.0 \times 10^{- 2} (k i l o g r a m) = 5.0 \times 10^{- 2} (k g)

Right side: 1.0 (a s s a y t o n) = \frac{7.0}{2.4 \times 10^{2}} (k i l o g r a m) = \frac{7.0}{2.4 \times 10^{2}} (k g)

Insert known values into the conversion equation to determine

x

1.0 (l i a n g (市 兩)) = x (a s s a y t o n)

Insert known values =>

1.0 \times 5.0 \times 10^{- 2} \times (k i l o g r a m) = x \times \frac{7.0}{2.4 \times 10^{2}} \times (k i l o g r a m)

Or

1.0 \cdot 5.0 \times 10^{- 2} \cdot (k g) = x \cdot \frac{7.0}{2.4 \times 10^{2}} \cdot (k g)

Cancel SI units

1.0 \times 5.0 \times 10^{- 2} \cdot (k g) = x \times \frac{7.0}{2.4 \times 10^{2}} \times (k g)

Conversion Equation

5.0 \times 10^{- 2} = x \times \frac{7.0}{2.4 \times 10^{2}}

Switch sides

x \times \frac{7.0}{2.4 \times 10^{2}} = 5.0 \times 10^{- 2}

Isolate

x

Multiply both sides by

(\frac{2.4 \times 10^{2}}{7.0})

x \times \frac{7.0}{2.4 \times 10^{2}} \times \frac{2.4 \times 10^{2}}{7.0} = 5.0 \times 10^{- 2} \times \frac{2.4 \times 10^{2}}{7.0}

Cancel

x \times \frac{7.0 \times 2.4 \times 10^{2}}{2.4 \times 10^{2} \times 7.0} = 5.0 \times 10^{- 2} \times \frac{2.4 \times 10^{2}}{7.0}

Simplify

x = \frac{5.0 \times 2.4}{7.0}

Solve

x

x \approx 1.7142857143 \approx 1.7143

Conversion Equation

1.0 (l i a n g (市 兩)) \approx 1.7143 (a s s a y t o n)

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