# Convert liang(市兩) to flask

Learn how to convert 1 liang(市兩) to flask step by step.

## Calculation Breakdown

Set up the equation
$$1.0\left(liang(市兩)\right)={\color{rgb(20,165,174)} x}\left(flask\right)$$
Define the base values of the selected units in relation to the SI unit $$\left({\color{rgb(230,179,255)} kilo}gram\right)$$
$$\text{Left side: 1.0 } \left(liang(市兩)\right) = {\color{rgb(89,182,91)} 5.0 \times 10^{-2}\left({\color{rgb(230,179,255)} kilo}gram\right)} = {\color{rgb(89,182,91)} 5.0 \times 10^{-2}\left({\color{rgb(230,179,255)} k}g\right)}$$
$$\text{Right side: 1.0 } \left(flask\right) = {\color{rgb(125,164,120)} 34.7\left({\color{rgb(230,179,255)} kilo}gram\right)} = {\color{rgb(125,164,120)} 34.7\left({\color{rgb(230,179,255)} k}g\right)}$$
Insert known values into the conversion equation to determine $${\color{rgb(20,165,174)} x}$$
$$1.0\left(liang(市兩)\right)={\color{rgb(20,165,174)} x}\left(flask\right)$$
$$\text{Insert known values } =>$$
$$1.0 \times {\color{rgb(89,182,91)} 5.0 \times 10^{-2}} \times {\color{rgb(89,182,91)} \left({\color{rgb(230,179,255)} kilo}gram\right)} = {\color{rgb(20,165,174)} x} \times {\color{rgb(125,164,120)} {\color{rgb(125,164,120)} 34.7}} \times {\color{rgb(125,164,120)} \left({\color{rgb(230,179,255)} kilo}gram\right)}$$
$$\text{Or}$$
$$1.0 \cdot {\color{rgb(89,182,91)} 5.0 \times 10^{-2}} \cdot {\color{rgb(89,182,91)} \left({\color{rgb(230,179,255)} k}g\right)} = {\color{rgb(20,165,174)} x} \cdot {\color{rgb(125,164,120)} 34.7} \cdot {\color{rgb(125,164,120)} \left({\color{rgb(230,179,255)} k}g\right)}$$
$$\text{Cancel SI units}$$
$$1.0 \times {\color{rgb(89,182,91)} 5.0 \times 10^{-2}} \cdot {\color{rgb(89,182,91)} \cancel{\left({\color{rgb(230,179,255)} k}g\right)}} = {\color{rgb(20,165,174)} x} \times {\color{rgb(125,164,120)} 34.7} \times {\color{rgb(125,164,120)} \cancel{\left({\color{rgb(230,179,255)} k}g\right)}}$$
$$\text{Conversion Equation}$$
$$5.0 \times 10^{-2} = {\color{rgb(20,165,174)} x} \times 34.7$$
Switch sides
$${\color{rgb(20,165,174)} x} \times 34.7 = 5.0 \times 10^{-2}$$
Isolate $${\color{rgb(20,165,174)} x}$$
Multiply both sides by $$\left(\dfrac{1.0}{34.7}\right)$$
$${\color{rgb(20,165,174)} x} \times 34.7 \times \dfrac{1.0}{34.7} = 5.0 \times 10^{-2} \times \dfrac{1.0}{34.7}$$
$$\text{Cancel}$$
$${\color{rgb(20,165,174)} x} \times {\color{rgb(255,204,153)} \cancel{34.7}} \times \dfrac{1.0}{{\color{rgb(255,204,153)} \cancel{34.7}}} = 5.0 \times 10^{-2} \times \dfrac{1.0}{34.7}$$
$$\text{Simplify}$$
$${\color{rgb(20,165,174)} x} = \dfrac{5.0 \times 10^{-2}}{34.7}$$
Solve $${\color{rgb(20,165,174)} x}$$
$${\color{rgb(20,165,174)} x}\approx0.0014409222\approx1.4409 \times 10^{-3}$$
$$\text{Conversion Equation}$$
$$1.0\left(liang(市兩)\right)\approx{\color{rgb(20,165,174)} 1.4409 \times 10^{-3}}\left(flask\right)$$