Convert newton • meter to pound-force • inch
Learn how to convert
1
newton • meter to
pound-force • inch
step by step.
Calculation Breakdown
Set up the equation
\(1.0\left(newton \times meter\right)={\color{rgb(20,165,174)} x}\left(pound-force \times inch\right)\)
Define the base values of the selected units in relation to the SI unit \(\left(newton \times meter\right)\)
\(\text{Left side: 1.0 } \left(newton \times meter\right) = {\color{rgb(89,182,91)} 1.0\left(newton \times meter\right)} = {\color{rgb(89,182,91)} 1.0\left(N \cdot m\right)}\)
\(\text{Right side: 1.0 } \left(pound-force \times inch\right) = {\color{rgb(125,164,120)} 0.112984829027617\left(newton \times meter\right)} = {\color{rgb(125,164,120)} 0.112984829027617\left(N \cdot m\right)}\)
Insert known values into the conversion equation to determine \({\color{rgb(20,165,174)} x}\)
\(1.0\left(newton \times meter\right)={\color{rgb(20,165,174)} x}\left(pound-force \times inch\right)\)
\(\text{Insert known values } =>\)
\(1.0 \times {\color{rgb(89,182,91)} 1.0} \times {\color{rgb(89,182,91)} \left(newton \times meter\right)} = {\color{rgb(20,165,174)} x} \times {\color{rgb(125,164,120)} {\color{rgb(125,164,120)} 0.112984829027617}} \times {\color{rgb(125,164,120)} \left(newton \times meter\right)}\)
\(\text{Or}\)
\(1.0 \cdot {\color{rgb(89,182,91)} 1.0} \cdot {\color{rgb(89,182,91)} \left(N \cdot m\right)} = {\color{rgb(20,165,174)} x} \cdot {\color{rgb(125,164,120)} 0.112984829027617} \cdot {\color{rgb(125,164,120)} \left(N \cdot m\right)}\)
\(\text{Cancel SI units}\)
\(1.0 \times {\color{rgb(89,182,91)} 1.0} \cdot {\color{rgb(89,182,91)} \cancel{\left(N \cdot m\right)}} = {\color{rgb(20,165,174)} x} \times {\color{rgb(125,164,120)} 0.112984829027617} \times {\color{rgb(125,164,120)} \cancel{\left(N \cdot m\right)}}\)
\(\text{Conversion Equation}\)
\(1.0 = {\color{rgb(20,165,174)} x} \times 0.112984829027617\)
\(\text{Simplify}\)
\(1.0 = {\color{rgb(20,165,174)} x} \times 0.112984829027617\)
Switch sides
\({\color{rgb(20,165,174)} x} \times 0.112984829027617 = 1.0\)
Isolate \({\color{rgb(20,165,174)} x}\)
Multiply both sides by \(\left(\dfrac{1.0}{0.112984829027617}\right)\)
\({\color{rgb(20,165,174)} x} \times 0.112984829027617 \times \dfrac{1.0}{0.112984829027617} = 1.0 \times \dfrac{1.0}{0.112984829027617}\)
\(\text{Cancel}\)
\({\color{rgb(20,165,174)} x} \times {\color{rgb(255,204,153)} \cancel{0.112984829027617}} \times \dfrac{1.0}{{\color{rgb(255,204,153)} \cancel{0.112984829027617}}} = 1.0 \times \dfrac{1.0}{0.112984829027617}\)
\(\text{Simplify}\)
\({\color{rgb(20,165,174)} x} = \dfrac{1.0}{0.112984829027617}\)
Solve \({\color{rgb(20,165,174)} x}\)
\({\color{rgb(20,165,174)} x}\approx8.8507457913\approx8.8507\)
\(\text{Conversion Equation}\)
\(1.0\left(newton \times meter\right)\approx{\color{rgb(20,165,174)} 8.8507}\left(pound-force \times inch\right)\)
