Convert petrol to bucket

Learn how to convert 1 petrol to bucket step by step.

Calculation Breakdown

Set up the equation

1.0 (p e t r o l) = x (b u c k e t)

Define the base values of the selected units in relation to the SI unit

(c u b i c m e t e r)

Left side: 1.0 (p e t r o l) = \frac{10.0}{7.2} (c u b i c m e t e r) = \frac{10.0}{7.2} (m^{3})

Right side: 1.0 (b u c k e t) = 1.818436 \times 10^{- 2} (c u b i c m e t e r) = 1.818436 \times 10^{- 2} (m^{3})

Insert known values into the conversion equation to determine

x

1.0 (p e t r o l) = x (b u c k e t)

Insert known values =>

1.0 \times \frac{10.0}{7.2} \times (c u b i c m e t e r) = x \times 1.818436 \times 10^{- 2} \times (c u b i c m e t e r)

Or

1.0 \cdot \frac{10.0}{7.2} \cdot (m^{3}) = x \cdot 1.818436 \times 10^{- 2} \cdot (m^{3})

Cancel SI units

1.0 \times \frac{10.0}{7.2} \cdot (m^{3}) = x \times 1.818436 \times 10^{- 2} \times (m^{3})

Conversion Equation

\frac{10.0}{7.2} = x \times 1.818436 \times 10^{- 2}

Switch sides

x \times 1.818436 \times 10^{- 2} = \frac{10.0}{7.2}

Isolate

x

Multiply both sides by

(\frac{1.0}{1.818436 \times 10^{- 2}})

x \times 1.818436 \times 10^{- 2} \times \frac{1.0}{1.818436 \times 10^{- 2}} = \frac{10.0}{7.2} \times \frac{1.0}{1.818436 \times 10^{- 2}}

Cancel

x \times 1.818436 \times 10^{- 2} \times \frac{1.0}{1.818436 \times 10^{- 2}} = \frac{10.0 \times 1.0}{7.2 \times 1.818436 \times 10^{- 2}}

Simplify

x = \frac{10.0}{7.2 \times 1.818436 \times 10^{- 2}}

Rewrite equation

\frac{1.0}{10^{- 2}} can be rewritten to 10^{2}

Rewrite

x = \frac{10^{2} \times 10.0}{7.2 \times 1.818436}

Simplify

x = \frac{{10.0}^{3}}{7.2 \times 1.818436}

Solve

x

x \approx 76.378211215 \approx 76.3782

Conversion Equation

1.0 (p e t r o l) \approx 76.3782 (b u c k e t)

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