Convert pottle to displacement ton
Learn how to convert
1
pottle to
displacement ton
step by step.
Calculation Breakdown
Set up the equation
\(1.0\left(pottle\right)={\color{rgb(20,165,174)} x}\left(displacement \text{ } ton\right)\)
Define the base values of the selected units in relation to the SI unit \(\left(cubic \text{ } meter\right)\)
\(\text{Left side: 1.0 } \left(pottle\right) = {\color{rgb(89,182,91)} 2.273045 \times 10^{-3}\left(cubic \text{ } meter\right)} = {\color{rgb(89,182,91)} 2.273045 \times 10^{-3}\left(m^{3}\right)}\)
\(\text{Right side: 1.0 } \left(displacement \text{ } ton\right) = {\color{rgb(125,164,120)} 9.9108963072 \times 10^{-1}\left(cubic \text{ } meter\right)} = {\color{rgb(125,164,120)} 9.9108963072 \times 10^{-1}\left(m^{3}\right)}\)
Insert known values into the conversion equation to determine \({\color{rgb(20,165,174)} x}\)
\(1.0\left(pottle\right)={\color{rgb(20,165,174)} x}\left(displacement \text{ } ton\right)\)
\(\text{Insert known values } =>\)
\(1.0 \times {\color{rgb(89,182,91)} 2.273045 \times 10^{-3}} \times {\color{rgb(89,182,91)} \left(cubic \text{ } meter\right)} = {\color{rgb(20,165,174)} x} \times {\color{rgb(125,164,120)} {\color{rgb(125,164,120)} 9.9108963072 \times 10^{-1}}} \times {\color{rgb(125,164,120)} \left(cubic \text{ } meter\right)}\)
\(\text{Or}\)
\(1.0 \cdot {\color{rgb(89,182,91)} 2.273045 \times 10^{-3}} \cdot {\color{rgb(89,182,91)} \left(m^{3}\right)} = {\color{rgb(20,165,174)} x} \cdot {\color{rgb(125,164,120)} 9.9108963072 \times 10^{-1}} \cdot {\color{rgb(125,164,120)} \left(m^{3}\right)}\)
\(\text{Cancel SI units}\)
\(1.0 \times {\color{rgb(89,182,91)} 2.273045 \times 10^{-3}} \cdot {\color{rgb(89,182,91)} \cancel{\left(m^{3}\right)}} = {\color{rgb(20,165,174)} x} \times {\color{rgb(125,164,120)} 9.9108963072 \times 10^{-1}} \times {\color{rgb(125,164,120)} \cancel{\left(m^{3}\right)}}\)
\(\text{Conversion Equation}\)
\(2.273045 \times 10^{-3} = {\color{rgb(20,165,174)} x} \times 9.9108963072 \times 10^{-1}\)
Cancel factors on both sides
\(\text{Cancel factors}\)
\(2.273045 \times {\color{rgb(255,204,153)} \cancelto{10^{-2}}{10^{-3}}} = {\color{rgb(20,165,174)} x} \times 9.9108963072 \times {\color{rgb(255,204,153)} \cancel{10^{-1}}}\)
\(\text{Simplify}\)
\(2.273045 \times 10^{-2} = {\color{rgb(20,165,174)} x} \times 9.9108963072\)
Switch sides
\({\color{rgb(20,165,174)} x} \times 9.9108963072 = 2.273045 \times 10^{-2}\)
Isolate \({\color{rgb(20,165,174)} x}\)
Multiply both sides by \(\left(\dfrac{1.0}{9.9108963072}\right)\)
\({\color{rgb(20,165,174)} x} \times 9.9108963072 \times \dfrac{1.0}{9.9108963072} = 2.273045 \times 10^{-2} \times \dfrac{1.0}{9.9108963072}\)
\(\text{Cancel}\)
\({\color{rgb(20,165,174)} x} \times {\color{rgb(255,204,153)} \cancel{9.9108963072}} \times \dfrac{1.0}{{\color{rgb(255,204,153)} \cancel{9.9108963072}}} = 2.273045 \times 10^{-2} \times \dfrac{1.0}{9.9108963072}\)
\(\text{Simplify}\)
\({\color{rgb(20,165,174)} x} = \dfrac{2.273045 \times 10^{-2}}{9.9108963072}\)
Solve \({\color{rgb(20,165,174)} x}\)
\({\color{rgb(20,165,174)} x}\approx0.0022934808\approx2.2935 \times 10^{-3}\)
\(\text{Conversion Equation}\)
\(1.0\left(pottle\right)\approx{\color{rgb(20,165,174)} 2.2935 \times 10^{-3}}\left(displacement \text{ } ton\right)\)
