Convert pound-force / square foot to meter of mercury

Learn how to convert 1 pound-force / square foot to meter of mercury step by step.

Calculation Breakdown

Set up the equation

1.0 (\frac{p o u n d - f o r c e}{s q u a r e f o o t}) = x (m e t e r o f m e r c u r y)

Define the base values of the selected units in relation to the SI unit

(p a s c a l)

Left side: 1.0 (\frac{p o u n d - f o r c e}{s q u a r e f o o t}) = \frac{4.4482216152605}{9.290304 \times 10^{- 2}} (p a s c a l) = \frac{4.4482216152605}{9.290304 \times 10^{- 2}} (P a)

Right side: 1.0 (m e t e r o f m e r c u r y) = 133322.387415 (p a s c a l) = 133322.387415 (P a)

Insert known values into the conversion equation to determine

x

1.0 (\frac{p o u n d - f o r c e}{s q u a r e f o o t}) = x (m e t e r o f m e r c u r y)

Insert known values =>

1.0 \times \frac{4.4482216152605}{9.290304 \times 10^{- 2}} \times (p a s c a l) = x \times 133322.387415 \times (p a s c a l)

Or

1.0 \cdot \frac{4.4482216152605}{9.290304 \times 10^{- 2}} \cdot (P a) = x \cdot 133322.387415 \cdot (P a)

Cancel SI units

1.0 \times \frac{4.4482216152605}{9.290304 \times 10^{- 2}} \cdot (P a) = x \times 133322.387415 \times (P a)

Conversion Equation

\frac{4.4482216152605}{9.290304 \times 10^{- 2}} = x \times 133322.387415

Switch sides

x \times 133322.387415 = \frac{4.4482216152605}{9.290304 \times 10^{- 2}}

Isolate

x

Multiply both sides by

(\frac{1.0}{133322.387415})

x \times 133322.387415 \times \frac{1.0}{133322.387415} = \frac{4.4482216152605}{9.290304 \times 10^{- 2}} \times \frac{1.0}{133322.387415}

Cancel

x \times 133322.387415 \times \frac{1.0}{133322.387415} = \frac{4.4482216152605 \times 1.0}{9.290304 \times 10^{- 2} \times 133322.387415}

Simplify

x = \frac{4.4482216152605}{9.290304 \times 10^{- 2} \times 133322.387415}

Rewrite equation

\frac{1.0}{10^{- 2}} can be rewritten to 10^{2}

Rewrite

x = \frac{10^{2} \times 4.4482216152605}{9.290304 \times 133322.387415}

Solve

x

x \approx 0.0003591314 \approx 3.5913 \times 10^{- 4}

Conversion Equation

1.0 (\frac{p o u n d - f o r c e}{s q u a r e f o o t}) \approx 3.5913 \times 10^{- 4} (m e t e r o f m e r c u r y)

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