Convert pound-force / square inch to atmosphere

Learn how to convert 1 pound-force / square inch to atmosphere step by step.

Calculation Breakdown

Set up the equation

1.0 (\frac{p o u n d - f o r c e}{s q u a r e i n c h}) = x (a t m o s p h e r e)

Define the base values of the selected units in relation to the SI unit

(p a s c a l)

Left side: 1.0 (\frac{p o u n d - f o r c e}{s q u a r e i n c h}) = \frac{4.4482216152605}{6.4516 \times 10^{- 4}} (p a s c a l) = \frac{4.4482216152605}{6.4516 \times 10^{- 4}} (P a)

Right side: 1.0 (a t m o s p h e r e) = 9.80665 \times 10^{5} (p a s c a l) = 9.80665 \times 10^{5} (P a)

Insert known values into the conversion equation to determine

x

1.0 (\frac{p o u n d - f o r c e}{s q u a r e i n c h}) = x (a t m o s p h e r e)

Insert known values =>

1.0 \times \frac{4.4482216152605}{6.4516 \times 10^{- 4}} \times (p a s c a l) = x \times 9.80665 \times 10^{5} \times (p a s c a l)

Or

1.0 \cdot \frac{4.4482216152605}{6.4516 \times 10^{- 4}} \cdot (P a) = x \cdot 9.80665 \times 10^{5} \cdot (P a)

Cancel SI units

1.0 \times \frac{4.4482216152605}{6.4516 \times 10^{- 4}} \cdot (P a) = x \times 9.80665 \times 10^{5} \times (P a)

Conversion Equation

\frac{4.4482216152605}{6.4516 \times 10^{- 4}} = x \times 9.80665 \times 10^{5}

Switch sides

x \times 9.80665 \times 10^{5} = \frac{4.4482216152605}{6.4516 \times 10^{- 4}}

Isolate

x

Multiply both sides by

(\frac{1.0}{9.80665 \times 10^{5}})

x \times 9.80665 \times 10^{5} \times \frac{1.0}{9.80665 \times 10^{5}} = \frac{4.4482216152605}{6.4516 \times 10^{- 4}} \times \frac{1.0}{9.80665 \times 10^{5}}

Cancel

x \times 9.80665 \times 10^{5} \times \frac{1.0}{9.80665 \times 10^{5}} = \frac{4.4482216152605 \times 1.0}{6.4516 \times 10^{- 4} \times 9.80665 \times {10^{5}}^{10}}

Simplify

x = \frac{4.4482216152605}{6.4516 \times 9.80665 \times 10.0}

Solve

x

x \approx 0.0070306958 \approx 7.0307 \times 10^{- 3}

Conversion Equation

1.0 (\frac{p o u n d - f o r c e}{s q u a r e i n c h}) \approx 7.0307 \times 10^{- 3} (a t m o s p h e r e)

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