Convert pound-force / square inch to torr

Learn how to convert 1 pound-force / square inch to torr step by step.

Calculation Breakdown

Set up the equation

1.0 (\frac{p o u n d - f o r c e}{s q u a r e i n c h}) = x (t o r r)

Define the base values of the selected units in relation to the SI unit

(p a s c a l)

Left side: 1.0 (\frac{p o u n d - f o r c e}{s q u a r e i n c h}) = \frac{4.4482216152605}{6.4516 \times 10^{- 4}} (p a s c a l) = \frac{4.4482216152605}{6.4516 \times 10^{- 4}} (P a)

Right side: 1.0 (t o r r) = \frac{101325.0}{760.0} (p a s c a l) = \frac{101325.0}{760.0} (P a)

Insert known values into the conversion equation to determine

x

1.0 (\frac{p o u n d - f o r c e}{s q u a r e i n c h}) = x (t o r r)

Insert known values =>

1.0 \times \frac{4.4482216152605}{6.4516 \times 10^{- 4}} \times (p a s c a l) = x \times \frac{101325.0}{760.0} \times (p a s c a l)

Or

1.0 \cdot \frac{4.4482216152605}{6.4516 \times 10^{- 4}} \cdot (P a) = x \cdot \frac{101325.0}{760.0} \cdot (P a)

Cancel SI units

1.0 \times \frac{4.4482216152605}{6.4516 \times 10^{- 4}} \cdot (P a) = x \times \frac{101325.0}{760.0} \times (P a)

Conversion Equation

\frac{4.4482216152605}{6.4516 \times 10^{- 4}} = x \times \frac{101325.0}{760.0}

Switch sides

x \times \frac{101325.0}{760.0} = \frac{4.4482216152605}{6.4516 \times 10^{- 4}}

Isolate

x

Multiply both sides by

(\frac{760.0}{101325.0})

x \times \frac{101325.0}{760.0} \times \frac{760.0}{101325.0} = \frac{4.4482216152605}{6.4516 \times 10^{- 4}} \times \frac{760.0}{101325.0}

Cancel

x \times \frac{101325.0 \times 760.0}{760.0 \times 101325.0} = \frac{4.4482216152605 \times 760.0}{6.4516 \times 10^{- 4} \times 101325.0}

Simplify

x = \frac{4.4482216152605 \times 760.0}{6.4516 \times 10^{- 4} \times 101325.0}

Rewrite equation

\frac{1.0}{10^{- 4}} can be rewritten to 10^{4}

Rewrite

x = \frac{10^{4} \times 4.4482216152605 \times 760.0}{6.4516 \times 101325.0}

Solve

x

x \approx 51.714932572 \approx 51.7149

Conversion Equation

1.0 (\frac{p o u n d - f o r c e}{s q u a r e i n c h}) \approx 51.7149 (t o r r)

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