Convert pound / bushel to tonne / cubic mile
Learn how to convert
1
pound / bushel to
tonne / cubic mile
step by step.
Calculation Breakdown
Set up the equation
\(1.0\left(\dfrac{pound}{bushel}\right)={\color{rgb(20,165,174)} x}\left(\dfrac{tonne}{cubic \text{ } mile}\right)\)
Define the base values of the selected units in relation to the SI unit \(\left(\dfrac{{\color{rgb(230,179,255)} kilo}gram}{cubic \text{ } meter}\right)\)
\(\text{Left side: 1.0 } \left(\dfrac{pound}{bushel}\right) = {\color{rgb(89,182,91)} \dfrac{45.359237}{3.636872}\left(\dfrac{{\color{rgb(230,179,255)} kilo}gram}{cubic \text{ } meter}\right)} = {\color{rgb(89,182,91)} \dfrac{45.359237}{3.636872}\left(\dfrac{{\color{rgb(230,179,255)} k}g}{m^{3}}\right)}\)
\(\text{Right side: 1.0 } \left(\dfrac{tonne}{cubic \text{ } mile}\right) = {\color{rgb(125,164,120)} \dfrac{1016.0469088}{4168181825.44058}\left(\dfrac{{\color{rgb(230,179,255)} kilo}gram}{cubic \text{ } meter}\right)} = {\color{rgb(125,164,120)} \dfrac{1016.0469088}{4168181825.44058}\left(\dfrac{{\color{rgb(230,179,255)} k}g}{m^{3}}\right)}\)
Insert known values into the conversion equation to determine \({\color{rgb(20,165,174)} x}\)
\(1.0\left(\dfrac{pound}{bushel}\right)={\color{rgb(20,165,174)} x}\left(\dfrac{tonne}{cubic \text{ } mile}\right)\)
\(\text{Insert known values } =>\)
\(1.0 \times {\color{rgb(89,182,91)} \dfrac{45.359237}{3.636872}} \times {\color{rgb(89,182,91)} \left(\dfrac{{\color{rgb(230,179,255)} kilo}gram}{cubic \text{ } meter}\right)} = {\color{rgb(20,165,174)} x} \times {\color{rgb(125,164,120)} {\color{rgb(125,164,120)} \dfrac{1016.0469088}{4168181825.44058}}} \times {\color{rgb(125,164,120)} \left(\dfrac{{\color{rgb(230,179,255)} kilo}gram}{cubic \text{ } meter}\right)}\)
\(\text{Or}\)
\(1.0 \cdot {\color{rgb(89,182,91)} \dfrac{45.359237}{3.636872}} \cdot {\color{rgb(89,182,91)} \left(\dfrac{{\color{rgb(230,179,255)} k}g}{m^{3}}\right)} = {\color{rgb(20,165,174)} x} \cdot {\color{rgb(125,164,120)} \dfrac{1016.0469088}{4168181825.44058}} \cdot {\color{rgb(125,164,120)} \left(\dfrac{{\color{rgb(230,179,255)} k}g}{m^{3}}\right)}\)
\(\text{Cancel SI units}\)
\(1.0 \times {\color{rgb(89,182,91)} \dfrac{45.359237}{3.636872}} \cdot {\color{rgb(89,182,91)} \cancel{\left(\dfrac{{\color{rgb(230,179,255)} k}g}{m^{3}}\right)}} = {\color{rgb(20,165,174)} x} \times {\color{rgb(125,164,120)} \dfrac{1016.0469088}{4168181825.44058}} \times {\color{rgb(125,164,120)} \cancel{\left(\dfrac{{\color{rgb(230,179,255)} k}g}{m^{3}}\right)}}\)
\(\text{Conversion Equation}\)
\(\dfrac{45.359237}{3.636872} = {\color{rgb(20,165,174)} x} \times \dfrac{1016.0469088}{4168181825.44058}\)
Switch sides
\({\color{rgb(20,165,174)} x} \times \dfrac{1016.0469088}{4168181825.44058} = \dfrac{45.359237}{3.636872}\)
Isolate \({\color{rgb(20,165,174)} x}\)
Multiply both sides by \(\left(\dfrac{4168181825.44058}{1016.0469088}\right)\)
\({\color{rgb(20,165,174)} x} \times \dfrac{1016.0469088}{4168181825.44058} \times \dfrac{4168181825.44058}{1016.0469088} = \dfrac{45.359237}{3.636872} \times \dfrac{4168181825.44058}{1016.0469088}\)
\(\text{Cancel}\)
\({\color{rgb(20,165,174)} x} \times \dfrac{{\color{rgb(255,204,153)} \cancel{1016.0469088}} \times {\color{rgb(99,194,222)} \cancel{4168181825.44058}}}{{\color{rgb(99,194,222)} \cancel{4168181825.44058}} \times {\color{rgb(255,204,153)} \cancel{1016.0469088}}} = \dfrac{45.359237 \times 4168181825.44058}{3.636872 \times 1016.0469088}\)
\(\text{Simplify}\)
\({\color{rgb(20,165,174)} x} = \dfrac{45.359237 \times 4168181825.44058}{3.636872 \times 1016.0469088}\)
Solve \({\color{rgb(20,165,174)} x}\)
\({\color{rgb(20,165,174)} x}\approx51164722.261\approx5.1165 \times 10^{7}\)
\(\text{Conversion Equation}\)
\(1.0\left(\dfrac{pound}{bushel}\right)\approx{\color{rgb(20,165,174)} 5.1165 \times 10^{7}}\left(\dfrac{tonne}{cubic \text{ } mile}\right)\)
