Convert pound / fluid-ounce to pound / barrel

Learn how to convert 1 pound / fluid-ounce to pound / barrel step by step.

Calculation Breakdown

Set up the equation
\(1.0\left(\dfrac{pound}{fluid-ounce}\right)={\color{rgb(20,165,174)} x}\left(\dfrac{pound}{barrel}\right)\)
Define the base values of the selected units in relation to the SI unit \(\left(\dfrac{{\color{rgb(230,179,255)} kilo}gram}{cubic \text{ } meter}\right)\)
\(\text{Left side: 1.0 } \left(\dfrac{pound}{fluid-ounce}\right) = {\color{rgb(89,182,91)} \dfrac{45359.237}{2.84130625}\left(\dfrac{{\color{rgb(230,179,255)} kilo}gram}{cubic \text{ } meter}\right)} = {\color{rgb(89,182,91)} \dfrac{45359.237}{2.84130625}\left(\dfrac{{\color{rgb(230,179,255)} k}g}{m^{3}}\right)}\)
\(\text{Right side: 1.0 } \left(\dfrac{pound}{barrel}\right) = {\color{rgb(125,164,120)} \dfrac{0.45359237}{0.119240471196}\left(\dfrac{{\color{rgb(230,179,255)} kilo}gram}{cubic \text{ } meter}\right)} = {\color{rgb(125,164,120)} \dfrac{0.45359237}{0.119240471196}\left(\dfrac{{\color{rgb(230,179,255)} k}g}{m^{3}}\right)}\)
Insert known values into the conversion equation to determine \({\color{rgb(20,165,174)} x}\)
\(1.0\left(\dfrac{pound}{fluid-ounce}\right)={\color{rgb(20,165,174)} x}\left(\dfrac{pound}{barrel}\right)\)
\(\text{Insert known values } =>\)
\(1.0 \times {\color{rgb(89,182,91)} \dfrac{45359.237}{2.84130625}} \times {\color{rgb(89,182,91)} \left(\dfrac{{\color{rgb(230,179,255)} kilo}gram}{cubic \text{ } meter}\right)} = {\color{rgb(20,165,174)} x} \times {\color{rgb(125,164,120)} {\color{rgb(125,164,120)} \dfrac{0.45359237}{0.119240471196}}} \times {\color{rgb(125,164,120)} \left(\dfrac{{\color{rgb(230,179,255)} kilo}gram}{cubic \text{ } meter}\right)}\)
\(\text{Or}\)
\(1.0 \cdot {\color{rgb(89,182,91)} \dfrac{45359.237}{2.84130625}} \cdot {\color{rgb(89,182,91)} \left(\dfrac{{\color{rgb(230,179,255)} k}g}{m^{3}}\right)} = {\color{rgb(20,165,174)} x} \cdot {\color{rgb(125,164,120)} \dfrac{0.45359237}{0.119240471196}} \cdot {\color{rgb(125,164,120)} \left(\dfrac{{\color{rgb(230,179,255)} k}g}{m^{3}}\right)}\)
\(\text{Cancel SI units}\)
\(1.0 \times {\color{rgb(89,182,91)} \dfrac{45359.237}{2.84130625}} \cdot {\color{rgb(89,182,91)} \cancel{\left(\dfrac{{\color{rgb(230,179,255)} k}g}{m^{3}}\right)}} = {\color{rgb(20,165,174)} x} \times {\color{rgb(125,164,120)} \dfrac{0.45359237}{0.119240471196}} \times {\color{rgb(125,164,120)} \cancel{\left(\dfrac{{\color{rgb(230,179,255)} k}g}{m^{3}}\right)}}\)
\(\text{Conversion Equation}\)
\(\dfrac{45359.237}{2.84130625} = {\color{rgb(20,165,174)} x} \times \dfrac{0.45359237}{0.119240471196}\)
Switch sides
\({\color{rgb(20,165,174)} x} \times \dfrac{0.45359237}{0.119240471196} = \dfrac{45359.237}{2.84130625}\)
Isolate \({\color{rgb(20,165,174)} x}\)
Multiply both sides by \(\left(\dfrac{0.119240471196}{0.45359237}\right)\)
\({\color{rgb(20,165,174)} x} \times \dfrac{0.45359237}{0.119240471196} \times \dfrac{0.119240471196}{0.45359237} = \dfrac{45359.237}{2.84130625} \times \dfrac{0.119240471196}{0.45359237}\)
\(\text{Cancel}\)
\({\color{rgb(20,165,174)} x} \times \dfrac{{\color{rgb(255,204,153)} \cancel{0.45359237}} \times {\color{rgb(99,194,222)} \cancel{0.119240471196}}}{{\color{rgb(99,194,222)} \cancel{0.119240471196}} \times {\color{rgb(255,204,153)} \cancel{0.45359237}}} = \dfrac{45359.237 \times 0.119240471196}{2.84130625 \times 0.45359237}\)
\(\text{Simplify}\)
\({\color{rgb(20,165,174)} x} = \dfrac{45359.237 \times 0.119240471196}{2.84130625 \times 0.45359237}\)
Solve \({\color{rgb(20,165,174)} x}\)
\({\color{rgb(20,165,174)} x}\approx4196.6778905\approx4.1967 \times 10^{3}\)
\(\text{Conversion Equation}\)
\(1.0\left(\dfrac{pound}{fluid-ounce}\right)\approx{\color{rgb(20,165,174)} 4.1967 \times 10^{3}}\left(\dfrac{pound}{barrel}\right)\)

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