Convert pound / fluid-ounce to ton / bushel

Learn how to convert 1 pound / fluid-ounce to ton / bushel step by step.

Calculation Breakdown

Set up the equation

1.0 (\frac{p o u n d}{f l u i d - o u n c e}) = x (\frac{t o n}{b u s h e l})

Define the base values of the selected units in relation to the SI unit

(\frac{k i l o g r a m}{c u b i c m e t e r})

Left side: 1.0 (\frac{p o u n d}{f l u i d - o u n c e}) = \frac{5.0}{2.84130625 \times 10^{- 4}} (\frac{k i l o g r a m}{c u b i c m e t e r}) = \frac{5.0}{2.84130625 \times 10^{- 4}} (\frac{k g}{m^{3}})

Right side: 1.0 (\frac{t o n}{b u s h e l}) = \frac{10^{5}}{3.636872} (\frac{k i l o g r a m}{c u b i c m e t e r}) = \frac{10^{5}}{3.636872} (\frac{k g}{m^{3}})

Insert known values into the conversion equation to determine

x

1.0 (\frac{p o u n d}{f l u i d - o u n c e}) = x (\frac{t o n}{b u s h e l})

Insert known values =>

1.0 \times \frac{5.0}{2.84130625 \times 10^{- 4}} \times (\frac{k i l o g r a m}{c u b i c m e t e r}) = x \times \frac{10^{5}}{3.636872} \times (\frac{k i l o g r a m}{c u b i c m e t e r})

Or

1.0 \cdot \frac{5.0}{2.84130625 \times 10^{- 4}} \cdot (\frac{k g}{m^{3}}) = x \cdot \frac{10^{5}}{3.636872} \cdot (\frac{k g}{m^{3}})

Cancel SI units

1.0 \times \frac{5.0}{2.84130625 \times 10^{- 4}} \cdot (\frac{k g}{m^{3}}) = x \times \frac{10^{5}}{3.636872} \times (\frac{k g}{m^{3}})

Conversion Equation

\frac{5.0}{2.84130625 \times 10^{- 4}} = x \times \frac{10^{5}}{3.636872}

Switch sides

x \times \frac{10^{5}}{3.636872} = \frac{5.0}{2.84130625 \times 10^{- 4}}

Isolate

x

Multiply both sides by

(\frac{3.636872}{10^{5}})

x \times \frac{10^{5}}{3.636872} \times \frac{3.636872}{10^{5}} = \frac{5.0}{2.84130625 \times 10^{- 4}} \times \frac{3.636872}{10^{5}}

Cancel

x \times \frac{10^{5} \times 3.636872}{3.636872 \times 10^{5}} = \frac{5.0 \times 3.636872}{2.84130625 \times 10^{- 4} \times {10^{5}}^{10}}

Simplify

x = \frac{5.0 \times 3.636872}{2.84130625 \times 10.0}

Solve

x

x = 0.64 = 6.4 \times 10^{- 1}

Conversion Equation

1.0 (\frac{p o u n d}{f l u i d - o u n c e}) = 6.4 \times 10^{- 1} (\frac{t o n}{b u s h e l})

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