Convert pound / hour to tonne / minute

Learn how to convert 1 pound / hour to tonne / minute step by step.

Calculation Breakdown

Set up the equation

1.0 (\frac{p o u n d}{h o u r}) = x (\frac{t o n n e}{m i n u t e})

Define the base values of the selected units in relation to the SI unit

(\frac{k i l o g r a m}{s e c o n d})

Left side: 1.0 (\frac{p o u n d}{h o u r}) = \frac{0.5}{3.6 \times 10^{3}} (\frac{k i l o g r a m}{s e c o n d}) = \frac{0.5}{3.6 \times 10^{3}} (\frac{k g}{s})

Right side: 1.0 (\frac{t o n n e}{m i n u t e}) = \frac{1016.0469088}{60.0} (\frac{k i l o g r a m}{s e c o n d}) = \frac{1016.0469088}{60.0} (\frac{k g}{s})

Insert known values into the conversion equation to determine

x

1.0 (\frac{p o u n d}{h o u r}) = x (\frac{t o n n e}{m i n u t e})

Insert known values =>

1.0 \times \frac{0.5}{3.6 \times 10^{3}} \times (\frac{k i l o g r a m}{s e c o n d}) = x \times \frac{1016.0469088}{60.0} \times (\frac{k i l o g r a m}{s e c o n d})

Or

1.0 \cdot \frac{0.5}{3.6 \times 10^{3}} \cdot (\frac{k g}{s}) = x \cdot \frac{1016.0469088}{60.0} \cdot (\frac{k g}{s})

Cancel SI units

1.0 \times \frac{0.5}{3.6 \times 10^{3}} \cdot (\frac{k g}{s}) = x \times \frac{1016.0469088}{60.0} \times (\frac{k g}{s})

Conversion Equation

\frac{0.5}{3.6 \times 10^{3}} = x \times \frac{1016.0469088}{60.0}

Switch sides

x \times \frac{1016.0469088}{60.0} = \frac{0.5}{3.6 \times 10^{3}}

Isolate

x

Multiply both sides by

(\frac{60.0}{1016.0469088})

x \times \frac{1016.0469088}{60.0} \times \frac{60.0}{1016.0469088} = \frac{0.5}{3.6 \times 10^{3}} \times \frac{60.0}{1016.0469088}

Cancel

x \times \frac{1016.0469088 \times 60.0}{60.0 \times 1016.0469088} = \frac{0.5 \times 60.0}{3.6 \times 10^{3} \times 1016.0469088}

Simplify

x = \frac{0.5 \times 60.0}{3.6 \times 10^{3} \times 1016.0469088}

Rewrite equation

\frac{1.0}{10^{3}} can be rewritten to 10^{- 3}

Rewrite

x = \frac{10^{- 3} \times 0.5 \times 60.0}{3.6 \times 1016.0469088}

Solve

x

x \approx 0.0000082017 \approx 8.2017 \times 10^{- 6}

Conversion Equation

1.0 (\frac{p o u n d}{h o u r}) \approx 8.2017 \times 10^{- 6} (\frac{t o n n e}{m i n u t e})

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