Convert pound / liter to gram / bushel

Learn how to convert 1 pound / liter to gram / bushel step by step.

Calculation Breakdown

Set up the equation

1.0 (\frac{p o u n d}{l i t e r}) = x (\frac{g r a m}{b u s h e l})

Define the base values of the selected units in relation to the SI unit

(\frac{k i l o g r a m}{c u b i c m e t e r})

Left side: 1.0 (\frac{p o u n d}{l i t e r}) = 5.0 \times 10^{2} (\frac{k i l o g r a m}{c u b i c m e t e r}) = 5.0 \times 10^{2} (\frac{k g}{m^{3}})

Right side: 1.0 (\frac{g r a m}{b u s h e l}) = \frac{1.0}{35.23907016688} (\frac{k i l o g r a m}{c u b i c m e t e r}) = \frac{1.0}{35.23907016688} (\frac{k g}{m^{3}})

Insert known values into the conversion equation to determine

x

1.0 (\frac{p o u n d}{l i t e r}) = x (\frac{g r a m}{b u s h e l})

Insert known values =>

1.0 \times 5.0 \times 10^{2} \times (\frac{k i l o g r a m}{c u b i c m e t e r}) = x \times \frac{1.0}{35.23907016688} \times (\frac{k i l o g r a m}{c u b i c m e t e r})

Or

1.0 \cdot 5.0 \times 10^{2} \cdot (\frac{k g}{m^{3}}) = x \cdot \frac{1.0}{35.23907016688} \cdot (\frac{k g}{m^{3}})

Cancel SI units

1.0 \times 5.0 \times 10^{2} \cdot (\frac{k g}{m^{3}}) = x \times \frac{1.0}{35.23907016688} \times (\frac{k g}{m^{3}})

Conversion Equation

5.0 \times 10^{2} = x \times \frac{1.0}{35.23907016688}

Switch sides

x \times \frac{1.0}{35.23907016688} = 5.0 \times 10^{2}

Isolate

x

Multiply both sides by

(\frac{35.23907016688}{1.0})

x \times \frac{1.0}{35.23907016688} \times \frac{35.23907016688}{1.0} = 5.0 \times 10^{2} \times \frac{35.23907016688}{1.0}

Cancel

x \times \frac{1.0 \times 35.23907016688}{35.23907016688 \times 1.0} = 5.0 \times 10^{2} \times \frac{35.23907016688}{1.0}

Simplify

x = 5.0 \times 10^{2} \times 35.23907016688

Solve

x

x = 17619.535083 \approx 1.762 \times 10^{4}

Conversion Equation

1.0 (\frac{p o u n d}{l i t e r}) \approx 1.762 \times 10^{4} (\frac{g r a m}{b u s h e l})

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