Convert pound / liter to pound / bushel

Learn how to convert 1 pound / liter to pound / bushel step by step.

Calculation Breakdown

Set up the equation

1.0 (\frac{p o u n d}{l i t e r}) = x (\frac{p o u n d}{b u s h e l})

Define the base values of the selected units in relation to the SI unit

(\frac{k i l o g r a m}{c u b i c m e t e r})

Left side: 1.0 (\frac{p o u n d}{l i t e r}) = 4.5359237 \times 10^{2} (\frac{k i l o g r a m}{c u b i c m e t e r}) = 4.5359237 \times 10^{2} (\frac{k g}{m^{3}})

Right side: 1.0 (\frac{p o u n d}{b u s h e l}) = \frac{5.0}{0.3636872} (\frac{k i l o g r a m}{c u b i c m e t e r}) = \frac{5.0}{0.3636872} (\frac{k g}{m^{3}})

Insert known values into the conversion equation to determine

x

1.0 (\frac{p o u n d}{l i t e r}) = x (\frac{p o u n d}{b u s h e l})

Insert known values =>

1.0 \times 4.5359237 \times 10^{2} \times (\frac{k i l o g r a m}{c u b i c m e t e r}) = x \times \frac{5.0}{0.3636872} \times (\frac{k i l o g r a m}{c u b i c m e t e r})

Or

1.0 \cdot 4.5359237 \times 10^{2} \cdot (\frac{k g}{m^{3}}) = x \cdot \frac{5.0}{0.3636872} \cdot (\frac{k g}{m^{3}})

Cancel SI units

1.0 \times 4.5359237 \times 10^{2} \cdot (\frac{k g}{m^{3}}) = x \times \frac{5.0}{0.3636872} \times (\frac{k g}{m^{3}})

Conversion Equation

4.5359237 \times 10^{2} = x \times \frac{5.0}{0.3636872}

Switch sides

x \times \frac{5.0}{0.3636872} = 4.5359237 \times 10^{2}

Isolate

x

Multiply both sides by

(\frac{0.3636872}{5.0})

x \times \frac{5.0}{0.3636872} \times \frac{0.3636872}{5.0} = 4.5359237 \times 10^{2} \times \frac{0.3636872}{5.0}

Cancel

x \times \frac{5.0 \times 0.3636872}{0.3636872 \times 5.0} = 4.5359237 \times 10^{2} \times \frac{0.3636872}{5.0}

Simplify

x = \frac{4.5359237 \times 10^{2} \times 0.3636872}{5.0}

Solve

x

x \approx 32.993147797 \approx 32.9931

Conversion Equation

1.0 (\frac{p o u n d}{l i t e r}) \approx 32.9931 (\frac{p o u n d}{b u s h e l})

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