Convert pound / liter to ton / bushel

Learn how to convert 1 pound / liter to ton / bushel step by step.

Calculation Breakdown

Set up the equation

1.0 (\frac{p o u n d}{l i t e r}) = x (\frac{t o n}{b u s h e l})

Define the base values of the selected units in relation to the SI unit

(\frac{k i l o g r a m}{c u b i c m e t e r})

Left side: 1.0 (\frac{p o u n d}{l i t e r}) = 5.0 \times 10^{2} (\frac{k i l o g r a m}{c u b i c m e t e r}) = 5.0 \times 10^{2} (\frac{k g}{m^{3}})

Right side: 1.0 (\frac{t o n}{b u s h e l}) = \frac{10^{5}}{3.636872} (\frac{k i l o g r a m}{c u b i c m e t e r}) = \frac{10^{5}}{3.636872} (\frac{k g}{m^{3}})

Insert known values into the conversion equation to determine

x

1.0 (\frac{p o u n d}{l i t e r}) = x (\frac{t o n}{b u s h e l})

Insert known values =>

1.0 \times 5.0 \times 10^{2} \times (\frac{k i l o g r a m}{c u b i c m e t e r}) = x \times \frac{10^{5}}{3.636872} \times (\frac{k i l o g r a m}{c u b i c m e t e r})

Or

1.0 \cdot 5.0 \times 10^{2} \cdot (\frac{k g}{m^{3}}) = x \cdot \frac{10^{5}}{3.636872} \cdot (\frac{k g}{m^{3}})

Cancel SI units

1.0 \times 5.0 \times 10^{2} \cdot (\frac{k g}{m^{3}}) = x \times \frac{10^{5}}{3.636872} \times (\frac{k g}{m^{3}})

Conversion Equation

5.0 \times 10^{2} = x \times \frac{10^{5}}{3.636872}

Cancel factors on both sides

Cancel factors

5.0 \times 10^{2} = x \times \frac{{10^{5}}^{10^{3}}}{3.636872}

Simplify

5.0 = x \times \frac{10^{3}}{3.636872}

Switch sides

x \times \frac{10^{3}}{3.636872} = 5.0

Isolate

x

Multiply both sides by

(\frac{3.636872}{10^{3}})

x \times \frac{10^{3}}{3.636872} \times \frac{3.636872}{10^{3}} = 5.0 \times \frac{3.636872}{10^{3}}

Cancel

x \times \frac{10^{3} \times 3.636872}{3.636872 \times 10^{3}} = 5.0 \times \frac{3.636872}{10^{3}}

Simplify

x = \frac{5.0 \times 3.636872}{10^{3}}

Rewrite equation

\frac{1.0}{10^{3}} can be rewritten to 10^{- 3}

Rewrite

x = 10^{- 3} \times 5.0 \times 3.636872

Solve

x

x = 0.01818436 \approx 1.8184 \times 10^{- 2}

Conversion Equation

1.0 (\frac{p o u n d}{l i t e r}) \approx 1.8184 \times 10^{- 2} (\frac{t o n}{b u s h e l})

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