Convert timber foot to peck

Learn how to convert 1 timber foot to peck step by step.

Calculation Breakdown

Set up the equation

1.0 (t i m b e r f o o t) = x (p e c k)

Define the base values of the selected units in relation to the SI unit

(c u b i c m e t e r)

Left side: 1.0 (t i m b e r f o o t) = 2.8316846592 \times 10^{- 2} (c u b i c m e t e r) = 2.8316846592 \times 10^{- 2} (m^{3})

Right side: 1.0 (p e c k) = 8.80976754172 \times 10^{- 3} (c u b i c m e t e r) = 8.80976754172 \times 10^{- 3} (m^{3})

Insert known values into the conversion equation to determine

x

1.0 (t i m b e r f o o t) = x (p e c k)

Insert known values =>

1.0 \times 2.8316846592 \times 10^{- 2} \times (c u b i c m e t e r) = x \times 8.80976754172 \times 10^{- 3} \times (c u b i c m e t e r)

Or

1.0 \cdot 2.8316846592 \times 10^{- 2} \cdot (m^{3}) = x \cdot 8.80976754172 \times 10^{- 3} \cdot (m^{3})

Cancel SI units

1.0 \times 2.8316846592 \times 10^{- 2} \cdot (m^{3}) = x \times 8.80976754172 \times 10^{- 3} \times (m^{3})

Conversion Equation

2.8316846592 \times 10^{- 2} = x \times 8.80976754172 \times 10^{- 3}

Cancel factors on both sides

Cancel factors

2.8316846592 \times 10^{- 2} = x \times 8.80976754172 \times {10^{- 3}}^{10^{- 1}}

Simplify

2.8316846592 = x \times 8.80976754172 \times 10^{- 1}

Switch sides

x \times 8.80976754172 \times 10^{- 1} = 2.8316846592

Isolate

x

Multiply both sides by

(\frac{1.0}{8.80976754172 \times 10^{- 1}})

x \times 8.80976754172 \times 10^{- 1} \times \frac{1.0}{8.80976754172 \times 10^{- 1}} = 2.8316846592 \times \frac{1.0}{8.80976754172 \times 10^{- 1}}

Cancel

x \times 8.80976754172 \times 10^{- 1} \times \frac{1.0}{8.80976754172 \times 10^{- 1}} = 2.8316846592 \times \frac{1.0}{8.80976754172 \times 10^{- 1}}

Simplify

x = \frac{2.8316846592}{8.80976754172 \times 10^{- 1}}

Rewrite equation

\frac{1.0}{10^{- 1}} can be rewritten to 10

Rewrite

x = \frac{10.0 \times 2.8316846592}{8.80976754172}

Solve

x

x \approx 3.2142558198 \approx 3.2143

Conversion Equation

1.0 (t i m b e r f o o t) \approx 3.2143 (p e c k)

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