Convert ton of oil to (gram • meter) / second

Learn how to convert 1 ton of oil to (gram • meter) / second step by step.

Calculation Breakdown

Set up the equation

1.0 (t o n o f o i l) = x (\frac{g r a m \times m e t e r}{s e c o n d})

Define the base values of the selected units in relation to the SI unit

(j o u l e)

Left side: 1.0 (t o n o f o i l) = 4.184 \times 10^{10} (j o u l e) = 4.184 \times 10^{10} (J)

Right side: 1.0 (\frac{g r a m \times m e t e r}{s e c o n d}) = 10^{- 3} (j o u l e) = 10^{- 3} (J)

Insert known values into the conversion equation to determine

x

1.0 (t o n o f o i l) = x (\frac{g r a m \times m e t e r}{s e c o n d})

Insert known values =>

1.0 \times 4.184 \times 10^{10} \times (j o u l e) = x \times 10^{- 3} \times (j o u l e)

Or

1.0 \cdot 4.184 \times 10^{10} \cdot (J) = x \cdot 10^{- 3} \cdot (J)

Cancel SI units

1.0 \times 4.184 \times 10^{10} \cdot (J) = x \times 10^{- 3} \times (J)

Conversion Equation

4.184 \times 10^{10} = x \times 10^{- 3}

Switch sides

x \times 10^{- 3} = 4.184 \times 10^{10}

Isolate

x

Multiply both sides by

(\frac{1.0}{10^{- 3}})

x \times 10^{- 3} \times \frac{1.0}{10^{- 3}} = 4.184 \times 10^{10} \times \frac{1.0}{10^{- 3}}

Cancel

x \times 10^{- 3} \times \frac{1.0}{10^{- 3}} = 4.184 \times 10^{10} \times \frac{1.0}{10^{- 3}}

Simplify

x = \frac{4.184 \times 10^{10}}{10^{- 3}}

Rewrite equation

\frac{1.0}{10^{- 3}} can be rewritten to 10^{3}

Rewrite

x = 10^{3} \times 4.184 \times 10^{10}

Simplify

x = 10^{13} \times 4.184

Solve

x

x = 4.184 \times 10^{13}

Conversion Equation

1.0 (t o n o f o i l) = 4.184 \times 10^{13} (\frac{g r a m \times m e t e r}{s e c o n d})

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