Convert ton / barrel to pound / cubic foot

Learn how to convert 1 ton / barrel to pound / cubic foot step by step.

Calculation Breakdown

Set up the equation

1.0 (\frac{t o n}{b a r r e l}) = x (\frac{p o u n d}{c u b i c f o o t})

Define the base values of the selected units in relation to the SI unit

(\frac{k i l o g r a m}{c u b i c m e t e r})

Left side: 1.0 (\frac{t o n}{b a r r e l}) = \frac{10^{4}}{1.6365924} (\frac{k i l o g r a m}{c u b i c m e t e r}) = \frac{10^{4}}{1.6365924} (\frac{k g}{m^{3}})

Right side: 1.0 (\frac{p o u n d}{c u b i c f o o t}) = \frac{45.359237}{2.8316846592} (\frac{k i l o g r a m}{c u b i c m e t e r}) = \frac{45.359237}{2.8316846592} (\frac{k g}{m^{3}})

Insert known values into the conversion equation to determine

x

1.0 (\frac{t o n}{b a r r e l}) = x (\frac{p o u n d}{c u b i c f o o t})

Insert known values =>

1.0 \times \frac{10^{4}}{1.6365924} \times (\frac{k i l o g r a m}{c u b i c m e t e r}) = x \times \frac{45.359237}{2.8316846592} \times (\frac{k i l o g r a m}{c u b i c m e t e r})

Or

1.0 \cdot \frac{10^{4}}{1.6365924} \cdot (\frac{k g}{m^{3}}) = x \cdot \frac{45.359237}{2.8316846592} \cdot (\frac{k g}{m^{3}})

Cancel SI units

1.0 \times \frac{10^{4}}{1.6365924} \cdot (\frac{k g}{m^{3}}) = x \times \frac{45.359237}{2.8316846592} \times (\frac{k g}{m^{3}})

Conversion Equation

\frac{10^{4}}{1.6365924} = x \times \frac{45.359237}{2.8316846592}

Switch sides

x \times \frac{45.359237}{2.8316846592} = \frac{10^{4}}{1.6365924}

Isolate

x

Multiply both sides by

(\frac{2.8316846592}{45.359237})

x \times \frac{45.359237}{2.8316846592} \times \frac{2.8316846592}{45.359237} = \frac{10^{4}}{1.6365924} \times \frac{2.8316846592}{45.359237}

Cancel

x \times \frac{45.359237 \times 2.8316846592}{2.8316846592 \times 45.359237} = \frac{10^{4} \times 2.8316846592}{1.6365924 \times 45.359237}

Simplify

x = \frac{10^{4} \times 2.8316846592}{1.6365924 \times 45.359237}

Solve

x

x \approx 381.45087669 \approx 3.8145 \times 10^{2}

Conversion Equation

1.0 (\frac{t o n}{b a r r e l}) \approx 3.8145 \times 10^{2} (\frac{p o u n d}{c u b i c f o o t})

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