Convert ton / bushel to pound / gallon

Learn how to convert 1 ton / bushel to pound / gallon step by step.

Calculation Breakdown

Set up the equation

1.0 (\frac{t o n}{b u s h e l}) = x (\frac{p o u n d}{g a l l o n})

Define the base values of the selected units in relation to the SI unit

(\frac{k i l o g r a m}{c u b i c m e t e r})

Left side: 1.0 (\frac{t o n}{b u s h e l}) = \frac{10^{5}}{3.523907016688} (\frac{k i l o g r a m}{c u b i c m e t e r}) = \frac{10^{5}}{3.523907016688} (\frac{k g}{m^{3}})

Right side: 1.0 (\frac{p o u n d}{g a l l o n}) = \frac{453.59237}{3.785411784} (\frac{k i l o g r a m}{c u b i c m e t e r}) = \frac{453.59237}{3.785411784} (\frac{k g}{m^{3}})

Insert known values into the conversion equation to determine

x

1.0 (\frac{t o n}{b u s h e l}) = x (\frac{p o u n d}{g a l l o n})

Insert known values =>

1.0 \times \frac{10^{5}}{3.523907016688} \times (\frac{k i l o g r a m}{c u b i c m e t e r}) = x \times \frac{453.59237}{3.785411784} \times (\frac{k i l o g r a m}{c u b i c m e t e r})

Or

1.0 \cdot \frac{10^{5}}{3.523907016688} \cdot (\frac{k g}{m^{3}}) = x \cdot \frac{453.59237}{3.785411784} \cdot (\frac{k g}{m^{3}})

Cancel SI units

1.0 \times \frac{10^{5}}{3.523907016688} \cdot (\frac{k g}{m^{3}}) = x \times \frac{453.59237}{3.785411784} \times (\frac{k g}{m^{3}})

Conversion Equation

\frac{10^{5}}{3.523907016688} = x \times \frac{453.59237}{3.785411784}

Switch sides

x \times \frac{453.59237}{3.785411784} = \frac{10^{5}}{3.523907016688}

Isolate

x

Multiply both sides by

(\frac{3.785411784}{453.59237})

x \times \frac{453.59237}{3.785411784} \times \frac{3.785411784}{453.59237} = \frac{10^{5}}{3.523907016688} \times \frac{3.785411784}{453.59237}

Cancel

x \times \frac{453.59237 \times 3.785411784}{3.785411784 \times 453.59237} = \frac{10^{5} \times 3.785411784}{3.523907016688 \times 453.59237}

Simplify

x = \frac{10^{5} \times 3.785411784}{3.523907016688 \times 453.59237}

Solve

x

x \approx 236.82249312 \approx 2.3682 \times 10^{2}

Conversion Equation

1.0 (\frac{t o n}{b u s h e l}) \approx 2.3682 \times 10^{2} (\frac{p o u n d}{g a l l o n})

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