Convert ton / bushel to pound / liter

Learn how to convert 1 ton / bushel to pound / liter step by step.

Calculation Breakdown

Set up the equation

1.0 (\frac{t o n}{b u s h e l}) = x (\frac{p o u n d}{l i t e r})

Define the base values of the selected units in relation to the SI unit

(\frac{k i l o g r a m}{c u b i c m e t e r})

Left side: 1.0 (\frac{t o n}{b u s h e l}) = \frac{10^{5}}{3.636872} (\frac{k i l o g r a m}{c u b i c m e t e r}) = \frac{10^{5}}{3.636872} (\frac{k g}{m^{3}})

Right side: 1.0 (\frac{p o u n d}{l i t e r}) = 5.0 \times 10^{2} (\frac{k i l o g r a m}{c u b i c m e t e r}) = 5.0 \times 10^{2} (\frac{k g}{m^{3}})

Insert known values into the conversion equation to determine

x

1.0 (\frac{t o n}{b u s h e l}) = x (\frac{p o u n d}{l i t e r})

Insert known values =>

1.0 \times \frac{10^{5}}{3.636872} \times (\frac{k i l o g r a m}{c u b i c m e t e r}) = x \times 5.0 \times 10^{2} \times (\frac{k i l o g r a m}{c u b i c m e t e r})

Or

1.0 \cdot \frac{10^{5}}{3.636872} \cdot (\frac{k g}{m^{3}}) = x \cdot 5.0 \times 10^{2} \cdot (\frac{k g}{m^{3}})

Cancel SI units

1.0 \times \frac{10^{5}}{3.636872} \cdot (\frac{k g}{m^{3}}) = x \times 5.0 \times 10^{2} \times (\frac{k g}{m^{3}})

Conversion Equation

\frac{10^{5}}{3.636872} = x \times 5.0 \times 10^{2}

Cancel factors on both sides

Cancel factors

\frac{{10^{5}}^{10^{3}}}{3.636872} = x \times 5.0 \times 10^{2}

Simplify

\frac{10^{3}}{3.636872} = x \times 5.0

Switch sides

x \times 5.0 = \frac{10^{3}}{3.636872}

Isolate

x

Multiply both sides by

(\frac{1.0}{5.0})

x \times 5.0 \times \frac{1.0}{5.0} = \frac{10^{3}}{3.636872} \times \frac{1.0}{5.0}

Cancel

x \times 5.0 \times \frac{1.0}{5.0} = \frac{10^{3} \times 1.0}{3.636872 \times 5.0}

Simplify

x = \frac{10^{3}}{3.636872 \times 5.0}

Solve

x

x \approx 54.992312075 \approx 54.9923

Conversion Equation

1.0 (\frac{t o n}{b u s h e l}) \approx 54.9923 (\frac{p o u n d}{l i t e r})

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