Convert ton / cubic yard to ton / gallon
Learn how to convert
1
ton / cubic yard to
ton / gallon
step by step.
Calculation Breakdown
Set up the equation
\(1.0\left(\dfrac{ton}{cubic \text{ } yard}\right)={\color{rgb(20,165,174)} x}\left(\dfrac{ton}{gallon}\right)\)
Define the base values of the selected units in relation to the SI unit \(\left(\dfrac{{\color{rgb(230,179,255)} kilo}gram}{cubic \text{ } meter}\right)\)
\(\text{Left side: 1.0 } \left(\dfrac{ton}{cubic \text{ } yard}\right) = {\color{rgb(89,182,91)} \dfrac{10^{4}}{7.64554857984}\left(\dfrac{{\color{rgb(230,179,255)} kilo}gram}{cubic \text{ } meter}\right)} = {\color{rgb(89,182,91)} \dfrac{10^{4}}{7.64554857984}\left(\dfrac{{\color{rgb(230,179,255)} k}g}{m^{3}}\right)}\)
\(\text{Right side: 1.0 } \left(\dfrac{ton}{gallon}\right) = {\color{rgb(125,164,120)} \dfrac{10^{6}}{3.785411784}\left(\dfrac{{\color{rgb(230,179,255)} kilo}gram}{cubic \text{ } meter}\right)} = {\color{rgb(125,164,120)} \dfrac{10^{6}}{3.785411784}\left(\dfrac{{\color{rgb(230,179,255)} k}g}{m^{3}}\right)}\)
Insert known values into the conversion equation to determine \({\color{rgb(20,165,174)} x}\)
\(1.0\left(\dfrac{ton}{cubic \text{ } yard}\right)={\color{rgb(20,165,174)} x}\left(\dfrac{ton}{gallon}\right)\)
\(\text{Insert known values } =>\)
\(1.0 \times {\color{rgb(89,182,91)} \dfrac{10^{4}}{7.64554857984}} \times {\color{rgb(89,182,91)} \left(\dfrac{{\color{rgb(230,179,255)} kilo}gram}{cubic \text{ } meter}\right)} = {\color{rgb(20,165,174)} x} \times {\color{rgb(125,164,120)} {\color{rgb(125,164,120)} \dfrac{10^{6}}{3.785411784}}} \times {\color{rgb(125,164,120)} \left(\dfrac{{\color{rgb(230,179,255)} kilo}gram}{cubic \text{ } meter}\right)}\)
\(\text{Or}\)
\(1.0 \cdot {\color{rgb(89,182,91)} \dfrac{10^{4}}{7.64554857984}} \cdot {\color{rgb(89,182,91)} \left(\dfrac{{\color{rgb(230,179,255)} k}g}{m^{3}}\right)} = {\color{rgb(20,165,174)} x} \cdot {\color{rgb(125,164,120)} \dfrac{10^{6}}{3.785411784}} \cdot {\color{rgb(125,164,120)} \left(\dfrac{{\color{rgb(230,179,255)} k}g}{m^{3}}\right)}\)
\(\text{Cancel SI units}\)
\(1.0 \times {\color{rgb(89,182,91)} \dfrac{10^{4}}{7.64554857984}} \cdot {\color{rgb(89,182,91)} \cancel{\left(\dfrac{{\color{rgb(230,179,255)} k}g}{m^{3}}\right)}} = {\color{rgb(20,165,174)} x} \times {\color{rgb(125,164,120)} \dfrac{10^{6}}{3.785411784}} \times {\color{rgb(125,164,120)} \cancel{\left(\dfrac{{\color{rgb(230,179,255)} k}g}{m^{3}}\right)}}\)
\(\text{Conversion Equation}\)
\(\dfrac{10^{4}}{7.64554857984} = {\color{rgb(20,165,174)} x} \times \dfrac{10^{6}}{3.785411784}\)
Cancel factors on both sides
\(\text{Cancel factors}\)
\(\dfrac{{\color{rgb(255,204,153)} \cancel{10^{4}}}}{7.64554857984} = {\color{rgb(20,165,174)} x} \times \dfrac{{\color{rgb(255,204,153)} \cancelto{10^{2}}{10^{6}}}}{3.785411784}\)
Switch sides
\({\color{rgb(20,165,174)} x} \times \dfrac{10^{2}}{3.785411784} = \dfrac{1.0}{7.64554857984}\)
Isolate \({\color{rgb(20,165,174)} x}\)
Multiply both sides by \(\left(\dfrac{3.785411784}{10^{2}}\right)\)
\({\color{rgb(20,165,174)} x} \times \dfrac{10^{2}}{3.785411784} \times \dfrac{3.785411784}{10^{2}} = \dfrac{1.0}{7.64554857984} \times \dfrac{3.785411784}{10^{2}}\)
\(\text{Cancel}\)
\({\color{rgb(20,165,174)} x} \times \dfrac{{\color{rgb(255,204,153)} \cancel{10^{2}}} \times {\color{rgb(99,194,222)} \cancel{3.785411784}}}{{\color{rgb(99,194,222)} \cancel{3.785411784}} \times {\color{rgb(255,204,153)} \cancel{10^{2}}}} = \dfrac{1.0 \times 3.785411784}{7.64554857984 \times 10^{2}}\)
\(\text{Simplify}\)
\({\color{rgb(20,165,174)} x} = \dfrac{3.785411784}{7.64554857984 \times 10^{2}}\)
Rewrite equation
\(\dfrac{1.0}{10^{2}}\text{ can be rewritten to }10^{-2}\)
\(\text{Rewrite}\)
\({\color{rgb(20,165,174)} x} = \dfrac{10^{-2} \times 3.785411784}{7.64554857984}\)
Solve \({\color{rgb(20,165,174)} x}\)
\({\color{rgb(20,165,174)} x}\approx0.0049511317\approx4.9511 \times 10^{-3}\)
\(\text{Conversion Equation}\)
\(1.0\left(\dfrac{ton}{cubic \text{ } yard}\right)\approx{\color{rgb(20,165,174)} 4.9511 \times 10^{-3}}\left(\dfrac{ton}{gallon}\right)\)
